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CAPITULO XIV

Operaciones con Fracciones
Ejercicio 128
Simplificar:
  1. x3 4 x+2 8 = 1 4 [x3 x+2 2 ] = 1 4 [ 2(x3 ) (x+2 ) 2 ] = 1 4 [ 2x6x2 2 ] = 1 4 [ x8 2 ] = x8 8
  2. a+5b a 2 b3 ab = 1 a [ a+5b a b3 b ] = 1 a [ b(a+5b ) a(b3 ) ab ] = 1 a [ ab +5 b 2 ab +3a ab ] = 1 a [ 3a+5 b 2 ab ] = 3a+5 b 2 a 2 b
  3. 2 3m n 2 1 2 m 2 n = 1 mn [ 2 3n 1 2m ] = 1 mn [ 2(2m ) 3n 6mn ] = 1 mn [ 4m3n 6mn ] = 4m3n 6 m 2 n 2
  4. a3 5ab 43a b 2 3 a 2 b 3 = 1 ab [ a3 5 43a b 2 3a b 2 ] = 1 ab [ 3a b 2 (a3 ) 5(43a b 2 ) 15a b 2 ] = 1 ab [ 3 a 2 b 2 9a b 2 20+15a b 2 15a b 2 ] = 1 ab [ 3 a 2 b 2 +6a b 2 20 15a b 2 ] = 3 a 2 b 2 +6a b 2 20 15 a 2 b 3
  5. 2a+3 4a a2 8a = 1 4a [2a+3 a2 2 ] = 1 4a [ 2(2a+3 ) (a2 ) 2 ] = 1 4a [ 4a+6a+2 2 ] = 1 4a [ 3a+8 2 ] = 3a+8 8a
  6. y2x 20x x3y 24y = 1 4 [ y2x 5x x3y 6y ] = 1 4 [ 6y(y2x ) 5x(x3y ) 30xy ] = 1 4 [ 6 y 2 12xy5 x 2 +15xy 30xy ] = 1 4 [ 6 y 2 +3xy5 x 2 30xy ] = 6 y 2 +3xy5 x 2 120xy
  7. x1 3 x2 4 x+3 6 = 4(x1 ) 3(x2 ) 2(x+3 ) 12 = 4x43x+ 6 2x 6 12 = x4 12 = x+4 12
  8. 3 5 2a+1 10a 4 a 2 +1 20 a 2 = 1 5 [3 2a+1 2a 4 a 2 +1 4 a 2 ] = 1 5 [ 12 a 2 2a(2a+1 ) (4 a 2 +1 ) 4 a 2 ] = 1 5 [ 12 a 2 4 a 2 2a4 a 2 1 4 a 2 ] = 1 5 [ 4 a 2 2a1 4 a 2 ] = 4 a 2 2a1 20 a 2
  9. 3 5x x1 3 x 2 x 2 +2x+3 15 x 3 = 1 x [ 3 5 x1 3x x 2 +2x+3 15 x 2 ] = 1 x [ 9 x 2 5x(x1 ) ( x 2 +2x+3 ) 15 x 2 ] = 1 x [ 9 x 2 5 x 2 +5x x 2 2x3 15 x 2 ] = 1 x [ 3 x 2 +3x3 15 x 2 ] = 3 ( x 2 +x1 ) x 3 = x 2 +x1 5 x 3
  10. 1 2a 2+b 3ab 5 6 a 2 b 3 = 1 a [ 1 2 2+b 3b 5 6a b 3 ] = 1 a [ 3a b 3 2a b 2 (2+b ) 5 6a b 3 ] = 1 a [ 3a b 3 4a b 2 2a b 3 5 6a b 3 ] = 1 a [ a b 3 4a b 2 5 6a b 3 ] = a b 3 4a b 2 5 6 a 2 b 3