Suma de polinomios
- Ejercicio 16
Para revolver este grupo de ejercicios vamos a relizar el siguiente proceso:
- Ordenar los polinomios
- Escribir los polinomios, uno debajo de otro de tal forma, que los téminos semejantes queden en la misma columna
- Reduciremos los terminos semejantes
-
3a+2b–c;2a+3b+c
3a+2b–
c
2a+3b+
c
¯
5a+5b
-
7a–4b+5c;–7a+4b–6c
7a
–
4b
+5c
–
7a
+
4b
–6c
¯
–c
-
m+n–p;–m–n+p
m
+
n
–
p
–
m
–
n
+
p
¯
0
-
9x–3y+5;–x–y+4;–5x+4y–9
9x–
–3y
+
5
–x–
y
+
4
–5x+
4y
–
9
¯
3x
-
a+b–c;2a+2b–2c;–3a–b+3c
a
+
b
–
c
2a
+2b–
2c
–
3a
–
b
+
3c
¯
2b
-
p+q+r;–2p–6q+3r;p+5q–8r
p
+
q
+r
–
2p
–
6q
+3r
p
+
5q
–8r
¯
–4r
-
–7x–4y+6z;10x–20y–8z;–5x+24y+2z
–7x–
4y
+
6z
10x–
20y
–
8z
–5x+
24y
+
2z
¯
–2x
-
–2m+3n–6;3m–8n+8;–5m+n–10
–2m+3n–6
3m–8n+8
–5m+n–10
¯
–4m–4n–8
-
–5a–2b–3c;7a–3b+5c;–8a+5b–3c
–5a–
2b
–3c
7a–
3b
+5c
–8a+
5b
–3c
¯
–6a–c
-
ab+bc+cd;–8ab–3bc–3cd;5ab+2bc+2cd
ab+
bc
+
cd
–8ab–
3bc
–
3cd
5ab+
2bc
+
2cd
¯
–2ab
-
ax–ay–az;–5ax–7ay–6az;4ax+9ay+8az
ax
–ay–az
–
5ax
–7ay–6az
4ax
+9ay+8az
¯
ay+az
-
5x–7y+8;–y+6–4x;9–3x+8y
5x–
7y
+8
–4x–
y
+6
–3x+
8y
+9
¯
–2x+23
-
–am+6mn–4s;6s–am–5mn;–2s–5mn+3am
–am+6mn–
4s
–am–5mn+
6s
3am–5mn–
2s
¯
am–4mn
-
2a+3b;6b–4c;–a+8c
2a+3b
6b–4c
–a+8c
¯
a+9b+4c
-
6m–3n;–4n+5p;–m–5p
6m–3n
–4n+
5p
–m–
5p
¯
5m–7n
-
8a+3b–c;5a–b+c;–a–b–c;7a–b–4c
8a+
3b
–
c
5a–
b
+
c
–a–
b
–c
7a–
b
–4c
¯
19a–5c
-
7x+2y–4;9y–6z+5;–y+3z–6;–5+8x–3y
7x+2y–4
9y–6z+
5
–y+3z–6
8x–3y–
5
¯
15x+7y–3z–10
-
–m–n–p;m+2n–5;3p–6m+4;2n+5m–8
–m–n–p
m
+2n–5
–
6m
3p+4
5m
+2n–8
¯
–m+3n+2p–9
-
5
a
x
–3
a
m
–7
a
n
;–8
a
x
+5
a
m
–9
a
n
;–11
a
x
+5
a
m
+16
a
n
5
a
x
–3
a
m
–
7
a
n
–8
a
x
+5
a
m
–
9
a
n
–11
a
x
+5
a
m
+
16
a
n
¯
–14
a
x
+7
a
m
-
6
m
a+1
–7
m
a+2
–5
m
a+3
;4
m
a+1
–7
m
a+2
–
m
a+3
;–5
m
a+1
+3
m
a+2
+12
m
a+3
6
m
a+1
–7
m
a+2
–5
m
a+3
4
m
a+1
–7
m
a+2
–
m
a+3
–5
m
a+1
+3
m
a+2
+12
m
a+3
¯
5
m
a+1
–11
m
a+2
+6
m
a+3
-
8x+y+z+u;–3x–4y–2z+3u;4x+5y+3z–4u;–9x–y+z+2u
8x
+y+
z
+
u
–
3x
–
4y
–
2z
+
3u
4x
+
5y
+3z–
4u
–
9x
–
y
+
z
+2u
¯
y+3z+2u
-
a+b–c+d;a–b+c–d;–2a+3b–2c+d;–3a–3b+4c–d
a
+
b
–
c
+
d
a
–
b
+
c
–
d
–
2a
+
3b
–2c+
d
–3a–
3b
+4c–
d
¯
–3a+2c
-
5ab–3bc+4cd;2bc+2cd–3dc;4bc–2ab+3de;5–3bc–6cd–ab
5ab–
3bc
+
4cd
2bc
+
2cd
–3dc
–2ab+
4bc
+3de
–ab–
3bc
–
6cd
+5
¯
3ab–3dc+3de+5
-
a–b;b–c;c+d;a–c;c–d;d–a;a–d
a
–
b
b
–
c
c
+
d
a–
c
c
–
d
–
a
+
d
a–
d
¯
2a
