Comparte esto 👍👍DESCARGACAPITULO XXX TEORIA DE LOS EXPONENTESEjercicio 225Dividir: a 2 entre a –2 a 2 ÷ a –2 = a 2 . a 2 = a 2+2 = a 4 x –3 entre x 2 x –3 ÷ x 2 = x –3 . x –2 = x –3–2 = x –5 m 1 2 entre m – 1 4 m 1 2 ÷ m – 1 4 = m 1 2 . m 1 4 = m 1 2 + 1 4 = m 3 4 a 2 entre a 5 a 2 ÷ a 5 = a 2 . a –5 = a 2–5 = a –3 x –3 entre x –7 x –3 ÷ x –7 = x –3 . x 7 = x –3+7 = x 4 a 1 2 entrea a 1 2 ÷ a = a 1 2 . a –1 = a 1 2 –1 = a – 1 2 x – 2 3 entre x – 1 3 x – 2 3 ÷ x – 1 3 = x – 2 3 . x 1 3 = x – 2 3 + 1 3 = x – 1 3 a 2 5 entre a – 1 5 a 2 5 ÷ a – 1 5 = a 2 5 . a 1 5 = a 2 5 + 1 5 = a 3 5 m – 3 4 entre m 1 2 m – 3 4 ÷ m 1 2 = m – 3 4 . m – 1 2 = m – 3 4 – 1 2 = m – 5 4 a 1 3 entrea a 1 3 ÷ a = a 1 3 . a –1 = a 1 3 –1 = a – 2 3 4 x 2 5 entre2 x – 1 5 4 x 2 5 ÷ 2 x – 1 5 =4 x 2 5 .2 x 1 5 =8 x 2 5 + 1 5 =8 x 3 5 a –3 entre a – 7 4 a –3 ÷ a – 7 4 = a –3 . a 7 4 = a –3+ 7 4 = a – 5 4 x –2 y –1 entre x –3 y –2 x –2 y –1 ÷ x –3 y –2 = x –2 y –1 . x 3 y 2 = x 3–2 y 2–1 =xy a 1 2 b 1 3 entreab a 1 2 b 1 3 ÷ ab = a 1 2 b 1 3 . a –1 b –1 = a 1 2 –1 b 1 3 –1 = a – 1 2 b – 2 3 a 2 b –3 entre a –1 b a 2 b –3 ÷ a –1 b = a 2 b –3 .a b –1 = a 2+1 b –3–1 = a 3 b –4 x – 1 2 y – 2 3 entre x – 1 2 y –1 x – 1 2 y – 2 3 ÷ x – 1 2 y –1 = x – 1 2 y – 2 3 . x 1 2 y = x – 1 2 + 1 2 y – 2 3 +1 = y 1 3 m 3 4 n – 3 4 entre m – 1 2 n 3 4 m 3 4 n – 3 4 ÷ m – 1 2 n 3 4 = m 3 4 n – 3 4 . m 1 2 n – 3 4 = m 3 4 + 1 2 n – 3 4 – 3 4 = m 5 4 n – 3 2 8 x –2 y 2 5 entre4x y – 1 5 8 x –2 y 2 5 ÷ 4x y – 1 5 =8 x –2 y 2 5 .4 x –1 y 1 5 =32 x –2–1 y 2 5 + 1 5 =32 x –3 y 3 5 a 1 3 bentre a – 1 4 b –3 a 1 3 b ÷ a – 1 4 b –3 = a 1 3 b. a 1 4 b 3 = a 1 3 + 1 4 b 1+3 = a 7 12 b 4 x –4 y –5 entre x 2 y –1 x –4 y –5 ÷ x 2 y –1 = x –4 y –5 . x –2 y = x –4–2 y –5+1 = x –6 y –4 Categories: Capítulo XXX