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Ejercicio 232

Gestor Baldor
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DESCARGA
CAPITULO XXXI

R a d i c a l e s
Simplificación de radicales
Ejercicio 232
Simplificar
  1. 1 5 = 1.5 5.5 = 5 5 2 = 1 5 5
  2. 3 8 = 3.2 8.2 = 6 2 4 = 1 2 2 6 = 1 4 6
  3. 2 1 2 =2 1.2 2.2 =2 2 2 2 = 2 2 2 = 2
  4. 3 1 6 =3 1.6 6.6 =3 6 6 2 = 3 6 = 1 2 6
  5. 1 2 2 3 = 1 2 2.3 3.3 = 1 2 6 3 2 = 1 2.3 6 = 1 6 6
  6. a 2 8x = a 2 .2x 8x.2x = 2 a 2 x 4 2 x 2 = a 4x 2x
  7. 3 2 4 a 2 27 y 3 = 3 2 2 2 a 2 .3y 3 3 y 3 .3y = 3 2 2 a 3y 3 4 y 4 = 3 a 3 2 y 2 3y = a 3 y 2 3y
  8. 5 9n 5 m 3 =5 9n.5m 5 m 3 .5m =5 3 2 n.5m 5 2 m 4 = 5 . 3 5 m 2 5mn = 3 m 2 5mn
  9. 6 5 a 3 24 x 2 =6 5 a 3 8.3 x 2 =6 5 a 2 a.6 2 3 .3 x 2 .6 =6 5 a 2 a.6 2 3 .3 x 2 .2.3 =6 30 a 2 a 2 4 . 3 2 x 2 = 6 a 2 2 . 3 x 30a = a 2x 30a
  10. 2 3 3 = 2. 3 2 3. 3 2 3 = 2. 3 2 3 3 3 = 1 3 183
  11. 5 1 5 3 =5 1. 5 2 5. 5 2 3 =5 5 2 5 3 3 = 5 5 253 = 253
  12. 8 9 x 2 3 = 8.3x 3 2 x 2 .3x 3 = 24x 3 3 x 3 3 = 1 3x 24x 3
  13. 2 b 2 125 4 b 5 3 =2 b 2 5 3 2 2 . b 5 3 =2 b 2 5 3 .2b 2 2 . b 5 .2b 3 =2 b 2 5 3 .2b 2 3 . b 6 3 = 2 b 2 2 b 2 5 2b 3 =5 2b 3
  14. 2 3 27 x 2 16 a 2 b 4 3 = 2 3 3 3 . x 2 4 2 a 2 b 4 3 = 2 3 3 3 . x 2 .4a b 2 4 2 a 2 b 4 .4a b 2 3 = 2 3 3 3 . x 2 .4a b 2 4 3 a 3 b 6 3 = 2 3 .a b 2 3 4a b 2 x 2 3 = 1 2a b 2 4a b 2 x 2 3
  15. 2xy 81 a 2 4 x 3 y 4 =2xy 3 4 a 2 2 2 x 3 y 4 =2xy 3 4 a 2 . 2 2 x y 3 2 2 x 3 y. 2 2 x y 3 4 =2xy 3 4 a 2 . 2 2 x y 3 2 4 x 4 y 4 4 = 2xy 2xy 3 4 a 2 x y 3 4 =3 4 a 2 x y 3 4
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