Comparte esto 👍👍DESCARGACAPITULO XXXI R a d i c a l e s Potenciación de radicalesEjercicio 245Desarollar: (4 2 ) 2 = 4 2 2 2 =16 × 2 =32 (2 3 ) 2 = 2 2 3 2 =4 × 3 =12 (5 7 ) 2 = 5 2 7 2 =25 × 7 =175 (2 43 ) 2 = 2 2 4 2 3 =4 2 4 3 =4 × 2 23 =8 23 (3 2 a 2 b 3 ) 4 = 3 4 (2 a 2 b ) 4 3 =81 2 4 a 8 b 4 3 =81 × 2 a 2 b 2 a 2 b 3 =162 a 2 b 2 a 2 b 3 ( 8 x 3 4 ) 2 = ( 2 3 x 3 ) 2 4 = 2 6 x 6 4 =2x (2x ) 2 =2x 2x ( 81a b 3 5 ) 3 = ( 9 2 a b 3 ) 3 5 = 9 6 a 3 b 9 5 =9b 9 a 3 b 4 5 (186 ) 3 = 1 8 3 = 18 = 3 2 × 2 =3 2 (4a 2x ) 2 = (4a ) 2 (2x ) 2 = 2 4 a 2 × 2x = 2 5 a 2 x =32 a 2 x (2 x+1 ) 2 = 2 2 (x+1 ) 2 =4(x+1 ) =4x+4 (3 x–a ) 2 = 3 2 (x–a ) 2 =9(x–a ) =9x–9a (4 9 a 3 b 4 6 ) 3 = 4 3 (9 a 3 b 4 ) 3 = 2 6 3 2 a 3 b 4 = 2 6 × 3a b 2 a =192a b 2 a Elevar al cuadrado: 2 – 3 = ( 2 – 3 ) 2 =2–2 2 × 3 +3 =5–2 6 4 2 + 3 = (4 2 + 3 ) 2 = (4 2 ) 2 +8 2 × 3 +3 = 2 4 2+8 6 +3 = 2 5 +8 6 +3 =32+8 6 +3 =35+8 6 5 – 7 = ( 5 – 7 ) 2 =5–2 5 × 7 +7 =12–2 35 5 7 –6 = (5 7 –6 ) 2 = (5 7 ) 2 –2 × 5 7 × 6+36 =25 × 7–60 7 +36 =175–60 7 +36 =211–60 7 x + x–1 = ( x + x–1 ) 2 = (x ) 2 +2 x × x–1 + ( x–1 ) 2 =x+2 x 2 –x +x–1 =2x+2 x 2 –x –1 x+1 –4 x = ( x+1 –4 x ) 2 = ( x+1 ) 2 –2 x+1 × 4 x + (4 x ) 2 =x+1–8 x 2 +x +16x =17x–8 x 2 +x +1 a+1 – a–1 = ( a+1 – a–1 ) 2 = ( a+1 ) 2 –2 a+1 × a–1 + ( a–1 ) 2 =a+ 1 –2 a 2 –1 +a– 1 =2a–2 a 2 –1 2 2x–1 + 2x+1 = (2 2x–1 + 2x+1 ) 2 = (2 2x–1 ) 2 +2 × 2 2x–1 × 2x+1 + ( 2x+1 ) 2 =4(2x–1 ) +4 4 x 2 –1 +2x+1 =8x–4+4 4 x 2 –1 +2x+1 =10x+4 4 x 2 –1 –3 Categories: Capítulo XXXI