Icono del sitio Solucionario Baldor

Ejercicio 249

Comparte esto πŸ‘πŸ‘
CAPITULO XXXI

R a d i c a l e s
RacionalizaciΓ³n de expresiones conjugadas
Ejercicio 249
Racionalizar el denominador de:
  1. 3 2 + 3 – 5 = 3 ( 2 + 3 ) – 5 Γ— 2 + 3 + 5 ( 2 + 3 ) + 5 = 3 ( 2 + 3 + 5 ) ( 2 + 3 ) 2 – ( 5 ) 2 = 6 + 3 2 + 15 2 +2 6 + 3 – 5 = 6 + 15 +3 2 6 = 6 + 15 +3 2 6 Γ— 6 6 = 6 2 + 10. 3 2 +3 6 2( 6 ) = 6+3 10 +3 6 2( 6 ) = 3 ( 2+ 10 + 6 ) 2 = 2+ 10 + 6 4
  2. 2 2 + 3 + 6 = 2 ( 2 + 3 ) + 6 Γ— 2 + 3 – 6 ( 2 + 3 ) – 6 = 2 ( 2 + 3 – 6 ) ( 2 + 3 ) 2 – ( 6 ) 2 = 2 2 + 6 – 3. 2 2 2+2 6 +3–6 = 2+ 6 –2 3 2 6 –1 Γ— 2 6 +1 2 6 +1 = 4 6 +2( 6 ) –4 18 +2+ 6 –2 3 ( 2 6 ) 2 –1 = 5 6 +14–4 2. 3 3 –2 3 4( 6 ) –1 = 5 6 –12 2 –2 3 +14 23
  3. 2– 3 2+ 3 + 5 = 2– 3 ( 2+ 3 ) + 5 Γ— 2+ 3 – 5 ( 2+ 3 ) – 5 = 4+ 2 3 –2 5 – 2 3 – 3 2 + 15 ( 2+ 3 ) 2 – ( 5 ) 2 = 4–2 5 –3+ 15 2 2 +4 3 +3–5 = 15 –2 5 +1 4 3 +2 Γ— 4 3 –2 4 3 –2 = 4 45 –8 15 +4 3 –2 15 +4 5 –2 ( 4 3 ) 2 – 2 2 = 4 5. 3 3 –10 15 +4 3 +4 5 –2 16( 3 ) –4 = 12 5 –10 15 +4 3 +4 5 –2 48–4 = 16 5 –10 15 +4 3 –2 44 = 2 ( 8 5 –5 15 +2 3 –1 ) = 8 5 –5 15 +2 3 –1 22
  4. 3 + 5 2 + 3 + 5 = 3 + 5 ( 2 + 3 ) + 5 Γ— 2 + 3 – 5 ( 2 + 3 ) – 5 = 6 + 3 2 – 15 + 10 + 15 – 5 2 ( 2 + 3 ) 2 – ( 5 ) 2 = 6 +3+ 10 –5 2 +2 6 + 3 – 5 = 6 + 10 –2 2 6 Γ— 6 6 = 6 2 + 60 –2 6 2( 6 ) = 6+ 2 2 .15 –2 6 2( 6 ) = 6+2 15 –2 6 2( 6 ) = 2 ( 3+ 15 – 6 ) 2 ( 6 ) = 3+ 15 – 6 6
  5. 6 + 3 + 2 6 + 3 – 2 = 6 + 3 + 2 ( 6 + 3 ) – 2 Γ— 6 + 3 + 2 ( 6 + 3 ) + 2 = ( 6 + 3 + 2 ) 2 ( 6 + 3 ) 2 – ( 2 ) 2 = 6+3+2+2 18 +2 12 +2 6 6+2 18 +3–2 = 11+2 2. 3 2 +2 3. 2 2 +2 6 7+2 2. 3 2 = 11+6 2 +4 3 +2 6 7+6 2 Γ— 7–6 2 7–6 2 = 77+42 2 +28 3 +14 6 –66 2 –36 2 2 –24 6 –12 12 7 2 – ( 6 2 ) 2 = 77+28 3 –24 2 –36( 2 ) –10 6 –12 3. 2 2 49–36( 2 ) = 77+28 3 –24 2 –72–10 6 –24 3 49–72 = 5+4 3 –24 2 –10 6 –23 = 10 6 –4 3 +24 2 –5 23
  6. 2 – 5 2 + 5 – 10 = 2 – 5 ( 2 + 5 ) – 10 Γ— 2 + 5 + 10 ( 2 + 5 ) + 10 = 2+ 10 + 20 – 10 –5– 50 ( 2 + 5 ) 2 – ( 10 ) 2 = –3+ 5. 2 2 – 5 2 .2 2+2 10 +5–10 = –3+2 5 –5 2 2 10 –3 Γ— 2 10 +3 2 10 +3 = –6 10 +4 50 –10 20 –9+6 5 –15 2 ( 2 10 ) 2 – 3 2 = –6 10 +4 5 2 .2 –10 5. 2 2 –9+6 5 –15 2 4( 10 ) –9 = –6 10 +20 2 –20 5 –9+6 5 –15 2 31 = 5 2 –6 10 –14 5 –9 31
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