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Ejercicio 263

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CAPITULO XXXII

CANTIDADES IMAGINARIAS
Ejercicio 263
Dividir:
  1. ( 1+ –1 ) Γ· ( 1– –1 ) 1+ –1 1– –1 = 1+ –1 1– –1 Γ— 1+ –1 1+ –1 = ( 1+ –1 ) 2 1 2 – ( –1 ) 2 = 1+2 –1 + ( –1 ) 2 1–( –1 ) = 1 +2 –1 – 1 1+1 = 2 –1 2 =i
  2. ( 3+ –1 ) Γ· ( 3– –1 ) = 3+ –1 3– –1 Γ— 3+ –1 3+ –1 = ( 3+ –1 ) 2 3 2 – ( –1 ) 2 = 9+6 –1 + ( –1 ) 2 9–( –1 ) = 9+6 –1 –1 9+1 = 8+6 –1 10 = 2 ( 4+3i ) = 4+3i 5
  3. ( 5–3 –1 ) Γ· ( 3+4 –1 ) = 5–3 –1 3+4 –1 Γ— 3–4 –1 3–4 –1 = ( 5–3i ) ( 3–4i ) 3 2 – ( 4i ) 2 = 15–20i–9i+12 i 2 9–16 i 2 = 15–29i+12( –1 ) 9–16( –1 ) = 15–29i–12 9+16 = 3–29i 25
  4. ( 8–5i ) Γ· ( 7+6i ) = 8–5i 7+6i Γ— 7–6i 7–6i = ( 8–5i ) ( 7–6i ) 7 2 – ( 6i ) 2 = 56–48i–35i+30 i 2 49–36 i 2 = 56–83i+30( –1 ) 49–36( –1 ) = 56–83i–30 49+36 = 26–83i 85
  5. ( 4+ –3 ) Γ· ( 5–4 –3 ) = 4+ –3 5–4 –3 Γ— 5+4 –3 5+4 –3 = ( 4+ 3 i ) ( 5+4 3 i ) 5 2 – ( 4 –3 ) 2 = 20+16 3 i+5 3 i+4( 3 i 2 ) 25–16( –3 ) = 20+21 3 i+12 i 2 25+48 = 20+21 3 i+12( –1 ) 73 = 20+21 3 i–12 73 = 8+21 3 i 73
  6. ( 2 +2 –5 ) Γ· ( 4 2 – –5 ) = 2 +2 –5 4 2 – –5 Γ— 4 2 + –5 4 2 + –5 = 2 +2 5 i 4 2 – 5 i Γ— 4 2 + 5 i 4 2 + 5 i = ( 2 +2 5 i ) ( 4 2 + 5 i ) ( 4 2 ) 2 – ( 5 i ) 2 = 4( 2 ) + 10 i+8 10 i+2( 5 ) i 2 16( 2 ) –5 i 2 = 8+9 10 i+10( –1 ) 32–5( –1 ) = 8+9 10 i–10 32+5 = –2+9 10 i 37
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