Comparte esto 👍👍DESCARGACAPITULO V División Hallar el valor numéricoEjercicio 60Hallar el volor numérico de las expresiones siguientes para a=–1,b=2,c=– 1 2 a 2 –2ab+ b 2 = (–1 ) 2 –2(–1 ) ( 2 ) + ( 2 ) 2 =1+4+4 =9 3 a 3 –4 a 2 b+3a b 2 – b 3 =3 (–1 ) 3 –4 ( 1 ) 2 ( 2 ) +3(–1 ) ( 2 ) 2 – ( 2 ) 3 =3(–1 ) –8–12–8 =–3–28 =–31 a 4 –3 a 3 +2ac–3bc = (–1 ) 4 –3 (–1 ) 3 + 2 (–1 ) (– 1 2 ) –3(2 ) (– 1 2 ) =1+3+1+3 =8 a 5 –8 a 4 c+16 a 3 c 2 –20 a 2 c 3 +40a c 4 – c 5 = (–1 ) 5 – (–1 ) 4 (– 1 2 ) +16 (–1 ) 3 (– 1 2 ) 2 –20 (–1 ) 2 (– 1 2 ) 3 +40(–1 ) (– 1 2 ) 4 – (– 1 2 ) 5 =–1+4–( 1 4 ) –(– 1 ) –( 1 ) + 1 32 =–1+ 4 – 4 + 5 2 – 5 2 + 1 32 = –32+1 32 =– 31 32 (a–b ) 2 + (b–c ) 2 – (a–c ) 2 = (–1–2 ) 2 + (2–[– 1 2 ] ) 2 – (–1–[– 1 2 ] ) 2 = (–3 ) 2 + (2+ 1 2 ) 2 – (–1+ 1 2 ) 2 =9+ ( 4+1 2 ) 2 – ( –2+1 2 ) 2 =9+ ( 5 2 ) 2 – (– 1 2 ) 2 =9+ 25 4 – 1 4 = 36+25–1 4 = 4 =15 (b+a ) 3 – (b–c ) 3 – (a–c ) 3 = (2+[–1 ] ) 3 – (2–[– 1 2 ] ) 3 – (–1–[– 1 2 ] ) 3 = (2–1 ) 3 – (2+ 1 2 ) 3 – (–1+ 1 2 ) 3 = ( 1 ) 3 – ( 4+1 2 ) 3 – ( –2+1 2 ) 3 =1– ( 5 2 ) 3 – (– 1 2 ) 3 =1– 125 8 + 1 8 = 8–125+1 8 =– =– 29 2 =–14 1 2 ab c + ac b – bc a = (–1 ) ( 2 ) – 1 2 + (–1 ) (– 1 2 ) 2 – (2 ) (– 1 2 ) (–1 ) =4+ 1 4 –1 = 16+1–4 4 = 13 3 =3 1 4 (a+b+c ) 2 – (a–b–c ) 2 +c = ([–1 ] +2+[– 1 2 ] ) 2 – ([–1 ] –2–[– 1 2 ] ) 2 +(– 1 2 ) = (1– 1 2 ) 2 – (–3+ 1 2 ) 2 – 1 2 = ( 2–1 2 ) 2 – ( –6+1 2 ) 2 – 1 2 = ( 1 2 ) 2 – (– 5 2 ) 2 – 1 2 = 1 4 – 25 4 – 1 2 = 1–25–2 4 =– =– 13 2 =–6 1 2 3(2a+b ) –4a(b+c ) –2c(a–b ) =3[2(–1 ) +2 ] –4(–1 ) [2+(– 1 2 ) ] – 2 (– 1 2 ) [(–1 ) –2 ] =+4( 4–1 2 ) +(–3 ) =( 3 2 ) –3 =6–3 =3 Hallar el valor numérico de las expresiones siguientes para a=2,b= 1 3 ,x=–2,y=–1,m=3,n= 1 2 x 4 8 – x 2 y 2 + 3x y 2 2 – y 3 = (–2 ) 4 8 – (–2 ) 2 (–1 ) 2 + 3(– 2 ) (–1 ) 2 2 – (–1 ) 3 =2+2–3+1 =2 (a–x ) 2 + (x–y ) 2 +( x 2 – y 2 ) (m+x–n ) = (2–[–2 ] ) 2 + (–2–[–1 ] ) 2 +( [–2 ] 2 – [–1 ] 2 ) (3+[–2 ] – 1 2 ) = ( 4 ) 2 + (–1 ) 2 +(4–1 ) ( 6–4–1 2 ) =16+1+3( 1 2 ) =17+ 3 2 = 34+3 2 = 37 2 =18 1 2 –(x–y ) +( x 2 + y 2 ) (x–y–m ) +3b(x+y+n ) =–[–2–(–1 ) ] +[ (–2 ) 2 + (–1 ) 2 ] [–2–(–1 ) –3 ] + 3 ( 1 3 ) (–2–1+ 1 2 ) =–[–2+1 ] +[4+1 ] [–5+1 ] +( –4–2+1 2 ) =1+5(–4 ) +(– 5 2 ) =1–20– 5 2 = 2–40–5 2 =– 43 2 =–21 1 2 (3x–2y ) (2n–4m ) +4 x 2 y 2 – x–y 2 =(3(–2 ) –2(–1 ) ) ( 2 ( 1 2 ) –4( 3 ) ) +4 (–2 ) 2 (–1 ) 2 – –2–(–1 ) 2 =(–6+2 ) (1–12 ) +4( 4 ) ( 1 ) – –2+1 2 =–4(–11 ) +16+ 1 2 =44+16+ 1 2 = 88+32+1 2 = 121 2 =60 1 2 4x 3y – x 2 2+ y 3 +( 1 n – 1 b ) x+ x 4 –m = 4(–2 ) 3(–1 ) – (–2 ) 3 2+ (–1 ) 3 +( 1 1 2 – 1 1 3 ) (–2 ) + (–2 ) 4 –3 = 8 3 + 8 2–1 +(2–3 ) (–2 ) +16–3 = 8 3 +8+(–1 ) (–2 ) +13 = 8 3 +21+2 = 8+63+6 3 = 77 3 =25 2 3 x 2 (x–y+m ) –(x–y ) ( x 2 + y 2 –n ) + (x+y ) 2 ( m 2 –2n ) = (–2 ) 2 [–2–(–1 ) +3 ] –[–2–(–1 ) ] [ (–2 ) 2 + (–1 ) 2 – 1 2 ] + [–2+(–1 ) ] 2 [ 3 2 – 2 ( 1 2 ) ] =4(–2+1+3 ) –(–2+1 ) (4+1– 1 2 ) + (–2–1 ) 2 (9–1 ) =4( 2 ) –(–1 ) ( 8+2–1 2 ) + (–3 ) 2 ( 8 ) =8+ 9 2 +72 = 16+9+144 2 = 169 2 =84 1 2 3a x + 2y m + 3n y – m n +2( x 3 – y 2 +4 ) = 3(2 ) – 2 + 2(–1 ) 3 + 3( 1 2 ) –1 – 3 1 2 +2[ (–2 ) 3 – (–1 ) 2 +4 ] =–3– 2 3 – 3 2 –6+2(–8–1+4 ) =–9– 2 3 – 3 2 +2(–5 ) = –54–4–9–60 6 =– 127 6 =–21 1 6 Categories: Capítulo V