▶️ Ejercicio 7 álgebra - Solucionario Baldor ✅✅

Comparte esto 👍👍

PRELIMINARES

Reducción de dos o más términos semejantes del mismo signo

Ejercicio 7

Para resolver estos problemas basta realizar la suma algebraica de los coeficientes de los términos que tengan la misma parte literaria:

$x + 2 x = 3 x$
$8 a + 9 a = 17 a$
$11 b + 9 b = 20 b$
$- b - 5 b = - 6 b$
$- 9 m - 7 m = - 16 m$
$- 8 m - m = - 9 m$
$4 a^{x} + 5 a^{x} = 9 a^{x}$
$6 a^{x + 1} + 8 a^{x + 1} = 14 a^{x + 1}$
$- m^{x + 1} - 5 m^{x + 1} = - 6 m^{x + 1}$
$- 3 a^{x - 2} - a^{x - 2} = - 4 a^{x - 2}$
$\frac{1}{2} a + \frac{1}{2} a = \frac{a + a}{2} = \frac{2 a}{2} = a$
$\frac{3}{5} a b + \frac{1}{10} a b = \frac{6 a b + a b}{10} = \frac{7 a b}{10}$
$\frac{1}{3} x y + \frac{1}{6} x y = \frac{2 x y + x y}{6} = \frac{3 x y}{6} = \frac{x y}{2}$
$- \frac{1}{5} x y - \frac{4}{5} x y = \frac{- x y - 4 x y}{5} = - \frac{5 x y}{5} = - x y$
$- \frac{5}{6} a^{2} b - \frac{1}{8} a^{2} b = \frac{- 20 a^{2} b - 3 a^{2} b}{24} = - \frac{23 a^{2} b}{24}$
$- a - \frac{7}{8} a = \frac{- 8 a - 7 a}{8} = - \frac{15 a}{8}$
$8 a + 9 a + 6 a + = 23 a$
$15 x + 20 x + x = 36 x$
$- 7 m - 8 m - 9 m = - 24 m$
$- a^{2} b - a^{2} b - 3 a^{2} b = - 5 - a^{2} b$
$a^{x} + 3 a^{x} + 8 a^{x} = 12 a^{x}$
$- 5 a^{x + 1} - 3 a^{x + 1} - 5 a^{x + 1} = - 13 a^{x + 1}$
$a + \frac{1}{2} a + \frac{2}{3} a = \frac{6 a + 3 a + 4 a}{6} = \frac{13 a}{6}$
$- x - \frac{2}{3} x - \frac{1}{6} x = \frac{- 6 x - 4 x - x}{6} = - \frac{11 x}{6}$
$\frac{1}{5} a x + \frac{3}{10} a x + a x = \frac{2 a x + 3 a x + 10 a x}{10} = \frac{15 a x}{10} = \frac{3 a x}{2}$
$- \frac{3}{4} a^{2} x - \frac{5}{6} a^{2} x - a^{2} x = \frac{- 9 a^{2} x - 10 a^{2} x - 12 a^{2} x}{12} = - \frac{31 a^{2} x}{12}$
$11 a + 8 a + 9 a + 11 a = 39 a$
$m^{x + 1} + 3 m^{x + 1} + 4 m^{x + 1} + 6 m^{x + 1} = 14 m^{x + 1}$
$- x^{2} y - 8 x^{2} y - 9 x^{2} y - 20 x^{2} y = - 38 x^{2} y$
$- 3 a^{m} - 5 a^{m} - 6 a^{m} - 9 a^{m} = - 23 a^{m}$
$\frac{1}{2} a + \frac{1}{4} a + \frac{1}{8} a + a = \frac{4 a + 2 a + a + 8 a}{8} = \frac{15 a}{8}$
$\frac{2}{5} a x + \frac{1}{2} a x + \frac{1}{10} a x + \frac{1}{20} a x = \frac{8 a x + 10 a x + 2 a x + a x}{20} = \frac{21 a x}{20}$
$0.5 m + 0.6 m + 0.7 m + 0.8 m = 2.6 m$
$- \frac{1}{7} a b - \frac{1}{14} a b - \frac{1}{28} a b - a b = \frac{- 4 a b - 2 a b - a b - 28 a b}{28} = - \frac{35 a b}{28} = - \frac{5 a b}{4}$
$- \frac{2}{3} x^{3} y - \frac{1}{6} x^{3} y - \frac{1}{9} x^{3} y - \frac{1}{12} x^{3} y = \frac{- 24 x^{3} y - 6 x^{3} y - 4 x^{3} y - 3 x^{3} y}{36} = - \frac{37 x^{3} y}{36}$
$a b^{2} + a b^{2} + 7 a b^{2} + 9 a b^{2} + 21 a b^{2} = 39 a b^{2}$
$- m - m - 8 m - 7 m - 3 m = - 20 m$
$- x^{a + 1} - 8 x^{a + 1} - 4 x^{a + 1} - 5 x^{a + 1} - x^{a + 1} = - 19 x^{a + 1}$
$\frac{1}{2} a + \frac{1}{3} a + \frac{1}{4} a + \frac{1}{5} a + \frac{1}{6} a = \frac{30 a + 20 a + 15 a + 12 a + 10 a}{60} = \frac{87}{60} a = \frac{29}{20} a$
$- \frac{1}{3} a b - \frac{1}{6} a b - \frac{1}{2} a b - \frac{1}{12} a b - \frac{1}{9} a b = \frac{- 12 a b - 6 a b - 18 a b - 3 a b - 4 a b}{36} = - \frac{43}{36} a b$