Comparte esto 👍👍DESCARGACAPITULO VIII Ecuaciones enteras de primer grado Ejercicio 81MISCELANIAResolver las siguientes ecuaciones: 14x–(3x–2 ) –[5x+2–(x–1 ) ] =0 14x–3x+2–[5x+2–x+1 ] =0 11x+2–(4x+3 ) =0 11x+2–4x–3 =0 7x–1 =0 7x =1 x = 1 7 (3x–7 ) 2 –5(2x+1 ) (x–2 ) =– x 2 –[–(3x+1 ) ] 9 x 2 –42x+49–5(2 x 2 –4x+x–2 ) =– x 2 +(3x+1 ) 9 x 2 –42x+49–10 x 2 +15x+10 =– x 2 +3x+1 – x 2 –27x+59 =– x 2 +3x+1 –27x–3x =–59+1 –30x =–58 x = – – x = 29 15 6x–(2x+1 ) =–{–5x+[–(–2x–1 ) ] } 6x–2x–1 =–{–5x+[2x+1 ] } 4x–1 =–{–5x+2x+1 } 4x–1 =–{–3x+1 } 4x– 1 =3x– 1 4x–3x =0 x =0 2x+3(– x 2 –1 ) =–{3 x 2 +2(x–1 ) –3(x+2 ) } 2x–3 x 2 –3 =–{3 x 2 +2x–2–3x–6 } 2x–3 x 2 –3 =–{3 x 2 –x–8 } 2x– 3 x 2 –3 =– 3 x 2 +x+8 2x–x =8+3 x =11 x 2 –{3x+[x(x+1 ) +4( x 2 –1 ) –4 x 2 ] } =0 x 2 –{3x+[ x 2 +x+ 4 x 2 –4– 4 x 2 ] } =0 x 2 –{3x+ x 2 +x–4 } =0 x 2 –{ x 2 +4x–4 } =0 x 2 – x 2 –4x+4 =0 –4x =–4 x = – 4 – 4 x =1 3(2x+1 ) (–x+3 ) – (2x+5 ) 2 =–[–{–3(x+5 ) } +10 x 2 ] 3(–2 x 2 +6x–x+3 ) –(4 x 2 +20x+25 ) =–[–{–3x–15 } +10 x 2 ] –6 x 2 +15x+9–4 x 2 –20x–25 =–[3x+15+10 x 2 ] – 10 x 2 –5x–16 =–3x–15– 10 x 2 –5x+3x =16–15 –2x =1 x =– 1 2 (x+1 ) (x+2 ) (x–3 ) =(x–2 ) (x+1 ) (x+1 ) ( x 2 +3x+2 ) (x–3 ) =( x 2 –x–2 ) (x+1 ) x 3 + 3 x 2 +2x– 3 x 2 –9x–6 = x 3 – x 2 –2x+ x 2 –x–2 –7x–6 =–3x–2 –7x+3x =6–2 –4x =4 x =– 4 4 x =–1 (x+2 ) (x+3 ) (x–1 ) =(x+4 ) (x+4 ) (x–4 ) +7 ( x 2 +5x+6 ) (x–1 ) =(x+4 ) ( x 2 –16 ) +7 x 3 +5 x 2 +6x– x 2 –5x–6 = x 3 –16x+4 x 2 –64+7 4 x 2 +x–6 = 4 x 2 –16x+ 4 x 2 –57 x+16x =6–57 17x =–51 x =– 17 x =–3 (x+1 ) 3 – (x–1 ) 3 =6x(x–3 ) [(x+1 ) –(x–1 ) ] [ (x+1 ) 2 +(x+1 ) (x–1 ) + (x–1 ) 2 ] =6 x 2 –18x [ x +1– x +1 ] [ x 2 + 2x + 1 + x 2 – 1 + x 2 – 2x +1 ] =6 x 2 –18x 2(3 x 2 +1 ) =6 x 2 –18x 6 x 2 +2 = 6 x 2 –18x – 2 =x x =– 1 9 3 (x–2 ) 2 (x+5 ) =3 (x+1 ) 2 (x–1 ) +3 Dividiendo la ecuación para 3 (x–2 ) 2 (x+5 ) = (x+1 ) 2 (x–1 ) +1 ( x 2 –4x+4 ) (x+5 ) =( x 2 +2x+1 ) (x–1 ) +1 x 3 –4 x 2 +4x+5 x 2 –20x+20 = x 3 +2 x 2 +x– x 2 –2x– 1 + 1 x 2 –16x+20 = x 2 –x –16x+x =–20 –15x =–20 x = – – x = 4 3 Categories: Capítulo VIII