Comparte esto 👍👍DESCARGACAPITULO XI Máximo común divisor de polinomios por descomposición en factores Ejercicio 112Hallar, por descomposición en factores, el m.c.d. de: 2 a 2 +2ab,4 a 2 –4ab 2 a 2 +2ab=2a(a+b ) 4 a 2 –4ab= 2 2 a(a–b ) m.c.d=2a 6 x 3 y–6 x 2 y,9 x 3 y 2 +18 x 2 y 2 6 x 3 y–6 x 2 y=2.3 x 2 y(x–1 ) 9 x 3 y 2 +18 x 2 y 2 = 3 2 x 2 y 2 (x+2 ) m.c.d=3 x 2 y 12 a 2 b 3 ,4 a 3 b 2 –8 a 2 b 3 12 a 2 b 3 =3.4 a 2 b 3 4 a 3 b 2 –8 a 2 b 3 =4 a 2 b 2 (a–2b ) m.c.d=4 a 2 b 2 ab+b, a 2 +a ab+b=b(a+1 ) a 2 +a=a(a+1 ) m.c.d=a+1 x 2 –x, x 3 – x 2 x 2 –x=x(x–1 ) x 3 – x 2 = x 2 (x–1 ) m.c.d=x–1 30a x 2 –15 x 3 ,10ax y 2 –20 x 2 y 2 30a x 2 –15 x 3 =5.3 x 2 (2a–x ) 10ax y 2 –20 x 2 y 2 =5.2x y 2 (a–2x ) m.c.d=5x 18 a 2 x 3 y 4 ,6 a 2 x 2 y 4 –18 a 2 x y 4 18 a 2 x 3 y 4 =3.6 a 2 x 3 y 4 6 a 2 x 2 y 4 –18 a 2 x y 4 =6 a 2 x y 4 (x–3 ) m.c.d=6 a 2 x y 4 5 a 2 –15a, a 3 –3 a 2 5 a 2 –15a=5a(a–3 ) a 3 –3 a 2 = a 2 (a–3 ) m.c.d=a(a–3 ) 3 x 3 +15 x 2 ,a x 2 +5ax 3 x 3 +15 x 2 =3 x 2 (x+5 ) a x 2 +5ax=ax(x+5 ) m.c.d=x(x+5 ) a 2 – b 2 , a 2 –2ab+ b 2 a 2 – b 2 =(a–b ) (a+b ) a 2 –2ab+ b 2 = (a–b ) 2 m.c.d=a–b m 3 + n 3 ,3am+3an m 3 + n 3 =(m+n ) ( m 2 –mn+ n 2 ) 3am+3an=3a(m+n ) m.c.d=m+n x 2 –4, x 3 –8 x 2 –4=(x–2 ) (x+2 ) x 3 –8=(x–2 ) ( x 2 +2x+4 ) m.c.d=x–2 2a x 2 +4ax, x 3 – x 2 –6x 2a x 2 +4ax=2ax(x+2 ) x 3 – x 2 –6x=x( x 2 –x–6 ) =x(x–3 ) (x+2 ) m.c.d=x(x+2 ) 9 x 2 –1,9 x 2 –6x+1 9 x 2 –1=(3x–1 ) (3x+1 ) 9 x 2 –6x+1= (3x–1 ) 2 m.c.d=3x–1 4 a 2 +4ab+ b 2 ,2 a 2 –2ab+ab– b 2 4 a 2 +4ab+ b 2 = (2a+b ) 2 2 a 2 –2ab+ab– b 2 =2a(a–b ) +b(a–b ) =(a–b ) (2a+b ) m.c.d=2a+b 3 x 2 +3x–60,6 x 2 –18x–24 3 x 2 +3x–60=3( x 2 +x–20 ) =3(x+5 ) (x–4 ) 6 x 2 –18x–24=6( x 2 –3x–4 ) =6(x–4 ) (x+1 ) m.c.d=3(x–4 ) 8 x 3 + y 3 ,4a x 2 –a y 2 8 x 3 + y 3 =(2x+y ) (4 x 2 –2xy+ y 2 ) 4a x 2 –a y 2 =a(4 x 2 – y 2 ) =a(2x–y ) (2x+y ) m.c.d=2x+y 2 a 3 –12 a 2 b+18a b 2 , a 3 x–9a b 2 x 2 a 3 –12 a 2 b+18a b 2 = 2a( a 2 –6ab+9 b 2 ) = 2a (a–3b ) 2 a 3 x–9a b 2 x =ax( a 2 –9 b 2 ) =ax(a–3b ) (a+3b ) m.c.d=a(a–3b ) ac+ad–2bc–2bd,2 c 2 +4cd+2 d 2 ac+ad–2bc–2bd =a(c+d ) –2b(c+d ) =(c+d ) (a–2b ) 2 c 2 +4cd+2 d 2 =2( c 2 +2cd+ d 2 ) =2 (c+d ) 2 m.c.d=c+d 3 a 2 m 2 +6 a 2 m–45 a 2 ,6a m 2 x+24amx–30ax 3 a 2 m 2 +6 a 2 m–45 a 2 =3 a 2 ( m 2 +2m–15 ) =3 a 2 (m+5 ) (m–3 ) 6a m 2 x+24amx–30ax =6ax( m 2 +4m–5 ) =6ax(m+5 ) (m–1 ) m.c.d=3a(m+5 ) 4 x 4 – y 2 , (2 x 2 –y ) 2 4 x 4 – y 2 =(2 x 2 –y ) (2 x 2 +y ) (2 x 2 –y ) 2 = (2 x 2 –y ) 2 m.c.d=2 x 2 –y 3 x 5 –3x,9 x 3 –9x 3 x 5 –3x =3x( x 4 –1 ) =3x( x 2 –1 ) ( x 2 +1 ) =3x(x–1 ) (x+1 ) ( x 2 +1 ) 9 x 3 –9x =9x( x 2 –1 ) =9x(x–1 ) (x+1 ) m.c.d=3x(x–1 ) a 2 +ab,ab+ b 2 , a 3 + a 2 b a 2 +ab =a(a+b ) ab+ b 2 =b(a+b ) a 3 + a 2 b = a 2 (a+b ) m.c.d=a(a+b ) 2 x 3 –2 x 2 ,3 x 2 –3x,4 x 3 –4 x 2 2 x 3 –2 x 2 =2 x 2 (x–1 ) 3 x 2 –3x =3x(x–1 ) 4 x 3 –4 x 2 =4 x 2 (x–1 ) m.c.d=x(x–1 ) x 4 –9 x 2 , x 4 –5 x 3 +6 x 2 , x 4 –6 x 3 +9 x 2 x 4 –9 x 2 = x 2 ( x 2 –9 ) = x 2 (x–3 ) (x+3 ) x 4 –5 x 3 +6 x 2 = x 2 ( x 2 –5x+6 ) = x 2 (x–3 ) (x–2 ) x 4 –6 x 3 +9 x 2 = x 2 ( x 2 –6x+9 ) = x 2 (x–3 ) 2 m.c.d= x 2 (x–3 ) a 3 b+2 a 2 b 2 +a b 3 , a 4 b– a 2 b 3 a 3 b+2 a 2 b 2 +a b 3 =ab( a 2 +2ab+ b 2 ) =ab (a+b ) 2 a 4 b– a 2 b 3 = a 2 b( a 2 – b 2 ) = a 2 b(a+b ) (a–b ) m.c.d=ab(a+b ) 2 x 2 +2x–4,2 x 2 –8x+6,2 x 3 –2 2 x 2 +2x–4 =2( x 2 +x–2 ) =2(x+2 ) (x–1 ) 2 x 2 –8x+6 =2( x 2 –4x+3 ) =2(x–3 ) (x–1 ) 2 x 3 –2 =2( x 3 –1 ) =2(x–1 ) ( x 2 +x+1 ) m.c.d=2(x–1 ) a x 3 –2a x 2 –8ax,a x 2 –ax–6a, a 2 x 3 –3 a 2 x 2 –10 a 2 x a x 3 –2a x 2 –8ax =ax( x 2 –2x–8 ) =ax(x–4 ) (x+2 ) a x 2 –ax–6a =a( x 2 –x–6 ) =a(x–3 ) (x+2 ) a 2 x 3 –3 a 2 x 2 –10 a 2 x = a 2 x( x 2 –3x–10 ) = a 2 x(x–5 ) (x+2 ) m.c.d=a(x+2 ) 2a n 4 –16a n 2 +32a,2a n 3 –8an,2 a 2 n 3 +16 a 2 2a n 4 –16a n 2 +32a =2a( n 4 –8 n 2 +16 ) =2a ( n 2 –4 ) 2 =2a [(n–2 ) (n+2 ) ] 2 =2a (n–2 ) 2 (n+2 ) 2 2a n 3 –8an =2an( n 2 –4 ) =2an(n–2 ) (n+2 ) 2 a 2 n 3 +16 a 2 =2 a 2 ( n 3 +8 ) =2 a 2 (n+2 ) ( n 2 –2n+4 ) m.c.d=2a(n+2 ) 4 a 2 +8a–12,2 a 2 –6a+4,6 a 2 +18a–24 4 a 2 +8a–12 =4( a 2 +2a–3 ) =4(a+3 ) (a–1 ) 2 a 2 –6a+4 =2( a 2 –3a+2 ) =2(a–2 ) (a–1 ) 6 a 2 +18a–24 =6( a 2 +3a–4 ) =6(a+4 ) (a–1 ) m.c.d=2(a–1 ) 4 a 2 – b 2 ,8 a 3 + b 3 ,4 a 2 +4ab+ b 2 4 a 2 – b 2 =(2a–b ) (2a+b ) 8 a 3 + b 3 =(2a+b ) (4 a 2 –2ab+ b 2 ) 4 a 2 +4ab+ b 2 = (2a+b ) 2 m.c.d=2a+b x 2 –2x–8, x 2 –x–12, x 3 –9 x 2 +20x x 2 –2x–8 =(x–4 ) (x+2 ) x 2 –x–12 =(x–4 ) (x+3 ) x 3 –9 x 2 +20x =x( x 2 –9x+20 ) =x(x–5 ) (x–4 ) m.c.d=x–4 a 2 +a, a 3 –6 a 2 –7a, a 6 +a a 2 +a =a(a+1 ) a 3 –6 a 2 –7a =a( a 2 –6a–7 ) =a(a–7 ) (a+1 ) a 6 +a =a( a 5 +1 ) =a(a+1 ) ( a 4 – a 3 + a 2 –a+1 ) m.c.d=a(a+1 ) x 3 +27,2 x 2 –6x+18, x 4 –3 x 3 +9 x 2 x 3 +27 =(x+3 ) ( x 2 –3x+9 ) 2 x 2 –6x+18 =2( x 2 –3x+9 ) x 4 –3 x 3 +9 x 2 = x 2 ( x 2 –3x+9 ) m.c.d= x 2 –3x+9 x 2 +ax–6 a 2 , x 2 +2ax–3 a 2 , x 2 +6ax+9 a 2 x 2 +ax–6 a 2 =(x+3a ) (x–2a ) x 2 +2ax–3 a 2 =(x+3a ) (x–a ) x 2 +6ax+9 a 2 = (x+3a ) 2 m.c.d=x+3a 54 x 3 +250,18a x 2 –50a,50+60x+18 x 2 54 x 3 +250 =2(27 x 3 +125 ) =2(3x+5 ) (9 x 2 –15x+25 ) 18a x 2 –50a =2a(9 x 2 –25 ) =2a(3x+5 ) (3x–5 ) 50+60x+18 x 2 =2(9 x 2 +30x+25 ) =2 (3x+5 ) 2 m.c.d=2(3x+5 ) ( x 2 –1 ) 2 , x 2 –4x–5, x 4 –1 ( x 2 –1 ) 2 = [(x+1 ) (x–1 ) ] 2 = (x+1 ) 2 (x–1 ) 2 x 2 –4x–5 =(x–4 ) (x+1 ) x 4 –1 =( x 2 +1 ) ( x 2 –1 ) =( x 2 +1 ) (x+1 ) (x–1 ) m.c.d=x+1 4a x 2 –28ax, a 2 x 3 –8 a 2 x 2 +7 a 2 x,a x 4 –15a x 3 +56a x 2 4a x 2 –28ax =4ax(x–7 ) a 2 x 3 –8 a 2 x 2 +7 a 2 x = a 2 x( x 2 –8x+7 ) = a 2 x(x–7 ) (x–1 ) a x 4 –15a x 3 +56a x 2 =a x 2 ( x 2 –15x+56 ) =a x 2 (x–8 ) (x–7 ) m.c.d=ax(x–7 ) 3 a 2 –6a, a 3 –4a, a 2 b–2ab, a 2 –a–2 3 a 2 –6a =3a(a–2 ) a 3 –4a =a( a 2 –4 ) =a(a–2 ) (a+2 ) a 2 b–2ab =ab(a–2 ) a 2 –a–2 =(a–2 ) (a+1 ) m.c.d=a–2 3 x 2 –x,27 x 3 –1,9 x 2 –6x+1,3ax–a+6x–2 3 x 2 –x =x(3x–1 ) 27 x 3 –1 =(3x–1 ) (9 x 2 +3x+1 ) 9 x 2 –6x+1 = (3x–1 ) 2 3ax–a+6x–2 =a(3x–1 ) +2(3x–1 ) =(3x–1 ) (a+2 ) m.c.d=3x–1 a 4 –1, a 3 + a 2 +a+1, a 3 x+ a 2 x+ax+x, a 5 + a 3 + a 2 +1 a 4 –1 =( a 2 +1 ) ( a 2 –1 ) =( a 2 +1 ) (a+1 ) (a–1 ) a 3 + a 2 +a+1 = a 2 (a+1 ) +(a+1 ) =(a+1 ) ( a 2 +1 ) a 3 x+ a 2 x+ax+x = a 2 x(a+1 ) +x(a+1 ) =(a+1 ) ( a 2 x+x ) =x(a+1 ) ( a 2 +1 ) a 5 + a 3 + a 2 +1 = a 3 ( a 2 +1 ) +( a 2 +1 ) =( a 2 +1 ) ( a 3 +1 ) =( a 2 +1 ) (a+1 ) ( a 2 –a+1 ) m.c.d=(a+1 ) ( a 2 +1 ) 2 m 2 +4mn+2 n 2 , m 3 + m 2 n+m n 2 + n 3 , m 3 + n 3 , m 3 –m n 2 2 m 2 +4mn+2 n 2 =2( m 2 +2mn+ n 2 ) =2 (m+n ) 2 m 3 + m 2 n+m n 2 + n 3 = m 2 (m+n ) + n 2 (m+n ) =(m+n ) ( m 2 + n 2 ) m 3 + n 3 =(m+n ) ( m 2 –mn+ n 2 ) m 3 –m n 2 =m( m 2 – n 2 ) =m(m–n ) (m+n ) m.c.d=m+n a 3 –3 a 2 +3a–1, a 2 –2a+1, a 3 –a, a 2 –4a+3 a 3 –3 a 2 +3a–1 =( a 3 –1 ) –3a(a–1 ) =(a–1 ) ( a 2 +a+1 ) –3a(a–1 ) =(a–1 ) ( a 2 +a+1–3a ) =(a–1 ) ( a 2 –2a+1 ) a 2 –2a+1 = (a–1 ) 2 a 3 –a =a( a 2 –1 ) =a(a–1 ) (a+1 ) a 2 –4a+3 =(a–3 ) (a–1 ) m.c.d=a–1 16 a 3 x+54x,12 a 2 x 2 –42a x 2 –90 x 2 ,32 a 3 x+24 a 2 x–36ax,32 a 4 x–144 a 2 x+162x 16 a 3 x+54x =2x(8 a 3 +27 ) =2x(2a+3 ) (4 a 2 –6a+9 ) 12 a 2 x 2 –42a x 2 –90 x 2 =6 x 2 (2 a 2 –7a–15 ) =6 x 2 (2 a 2 –10a+3a–15 ) =6 x 2 [2a(a–5 ) +3(a–5 ) ] =6 x 2 (a–5 ) (2a+3 ) 32 a 3 x+24 a 2 x–36ax =4ax(8 a 2 +6a–9 ) =4ax(8 a 2 +12a–6a–9 ) =4ax[4a(2a+3 ) –3(2a+3 ) ] =4ax(2a+3 ) (4a–3 ) 32 a 4 x–144 a 2 x+162x =2x(16 a 4 –72 a 2 +81 ) =2x (4 a 2 –9 ) 2 =2x [(2a–3 ) (2a+3 ) ] 2 =2x (2a–3 ) 2 (2a+3 ) 2 m.c.d=2x(2a+3 ) (xy+ y 2 ) 2 , x 2 y–2x y 2 –3 y 3 ,a x 3 y+a y 4 , x 2 y– y 3 (xy+ y 2 ) 2 = [y(x+y ) ] 2 = y 2 (x+y ) 2 x 2 y–2x y 2 –3 y 3 =y( x 2 –2xy–3 y 2 ) =y(x–3 ) (x+1 ) a x 3 y+a y 4 =ay( x 3 + y 4 ) x 2 y– y 3 =y( x 2 – y 2 ) =y(x–y ) (x+y ) m.c.d=y 2 a 2 –am+4a–2m,2a m 2 – m 3 ,6 a 2 +5am–4 m 2 ,16 a 2 +72am–40 m 2 2 a 2 –am+4a–2m =a(2a–m ) +2(2a–m ) =(2a–m ) (a+2 ) 2a m 2 – m 3 = m 2 (2a–m ) 6 a 2 +5am–4 m 2 =6 a 2 –3am+8am–4 m 2 =3a(2a–m ) +4m(2a–m ) =(2a–m ) (3a+4m ) 16 a 2 +72am–40 m 2 =8(2 a 2 +9am–5 m 2 ) =8(2 a 2 –am+10am–5 m 2 ) =8[a(2a–m ) +5m(2a–m ) ] =8(2a–m ) (a+5m ) m.c.d=2a–m 12ax–6ay+24bx–12by,3 a 3 +24 b 3 ,9 a 2 +9ab–18 b 2 ,12 a 2 +24ab 12ax–6ay+24bx–12by =6a(2x–y ) +12b(2x–y ) =(2x–y ) (6a+12b ) =6(2x–y ) (a+2b ) 3 a 3 +24 b 3 =3( a 3 +8 b 3 ) =3(a+2b ) ( a 2 –2ab+4 b 2 ) 9 a 2 +9ab–18 b 2 =9( a 2 +ab–2 b 2 ) =9(a+2b ) (a–b ) 12 a 2 +24ab =12a(a+2b ) m.c.d=a+2b 5 a 2 +5ax+5ay+5xy,15 a 3 –15a x 2 +15 a 2 y–15 x 2 y,20 a 3 –20a y 2 +20 a 2 x–20x y 2 ,5 a 5 +5 a 4 x+5 a 2 y 3 +5ax y 3 5 a 2 +5ax+5ay+5xy =5a(a+x ) +5y(a+x ) =(a+x ) (5a+5y ) =5(a+x ) (a+y ) 15 a 3 –15a x 2 +15 a 2 y–15 x 2 y =15 a 3 +15 a 2 y–15a x 2 –15 x 2 y =15 a 2 (a+y ) –15 x 2 (a+y ) =(a+y ) (15 a 2 –15 x 2 ) =15(a+y ) ( a 2 – x 2 ) =15(a+y ) (a+x ) (a–x ) 20 a 3 –20a y 2 +20 a 2 x–20x y 2 =20a( a 2 – y 2 ) +20x( a 2 – y 2 ) =( a 2 – y 2 ) (20a+20x ) =20(a+y ) (a–y ) (a+x ) 5 a 5 +5 a 4 x+5 a 2 y 3 +5ax y 3 =5 a 4 (a+x ) +5a y 3 (a+x ) =(a+x ) (5 a 4 +5a y 3 ) =(a+x ) 5a( a 3 + y 3 ) =5a(a+x ) (a+y ) ( a 2 –ay+ y 2 ) m.c.d=5(a+x ) (a+y ) Categories: Capítulo XI