- Ejercicio 10
problemas se tiene que agrupar todos los terminos de la misma clase, se
reducen los términos de cada clase y obtenemos el polinomio resultante
-
7a–9b+6a–4b=(
–9b–4b
)
+(7a+6a
)
=13a–13b -
a+b–c–b–c+2c–a=++=0
-
5x–11y–9+20x–1–y=(
5x+20x
)
+(–11y–y
)
+(–9–1
)
=25x–12y–10 -
–6m+8n+5–m–n–6m–11=(
–6m–m
)
+(8n–n
)
+(5–11
)
=–7m+7n–6 -
–a+b+2b–2c+3a+2c–3b=(
–a+3a
)
++=2a -
–81x+19y–30z+6y+80x+x–25y=+–30z=–30z
-
15
a
2
–6ab–8
a
2
+20–5ab–31+
a
2
–ab=(15
a
2
–8
a
2
+
a
2
)
+(–6ab–ab–5ab
)
+(20–31
)
=8
a
2
–12ab–11 -
–3a+4b–6a+81b–114b+31a–a–b=(
–3a–6a+31a–a
)
+(4b+81b–114b–b
)
=21a–30 -
–71
a
3
b–84
a
4
b
2
+50
a
3
b+84
a
4
b
2
–45
a
3
b+18
a
3
b=+(–71
a
3
b+50
a
3
b–45
a
3
b+18
a
3
b
)
=–48
a
3
b -
–a+b–c+8+2a+2b–19–2c–3a–3–3b+3c=+++(
8–19–3
)
=–14 -
m
2
+71mn–14
m
2
–65mn+
m
3
–
m
2
–115
m
2
+6
m
3
=(
m
3
+6
m
3
)
+(
m
2
–14
m
2
–
m
2
–115
m
2
)
+(71mn–65mn
)
=7
m
3
–129
m
2
+6mn -
x
4
y–
x
3
y
2
+
x
2
y–8
x
4
y–
x
2
y–10+
x
3
y
2
–7
x
3
y
2
–9+21
x
4
y–
y
3
+50
=
(
x
4
y–8
x
4
y+21
x
4
y
)
+(–
x
3
y
2
+
x
3
y
2
–7
x
3
y
2
)
+(
x
2
y
–
x
2
y
)
–
y
3
+(–10–9+50
)=
14
x
4
y–7
x
3
y
2
–
y
3
+31
-
5
a
x+1
–3
b
x+2
–8
c
x+3
–5
a
x+1
–50+4
b
x+2
–65–
b
x+2
+90+
c
x+3
+7
c
x+3
=
+++(–50–65+90
)=
–25
-
a
m+2
–
x
m+3
–5+8–3
a
m+2
+5
x
m+3
–6+
a
m+2
–5
x
m+3
=
(
a
m+2
–3
a
m+2
+
a
m+2
)
+(5
x
m+3
–
x
m+3
–5
x
m+3
)
+(–5+8–6
)=
–
a
m+2
–
x
m+3
–3
-
0.3a+0.4b+0.5c–0.6a–0.7b–0.9c+3a–3b–3c
=
(0.3a–0.6a+3a
)
+(0.4b–0.7b–3b
)
+(0.5c–0.9c–3c
)=
2.7a–3.3b–3.4c
-
1
2
a+
1
3
b+2a–3b–
3
4
a–
1
6
b+
3
4
–
1
2
=
(
1
2
a+2a–
3
4
a
)
+(
1
3
b–3b–
1
6
b
)
+(
3
4
–
1
2
)
=
2a+8a–3a
4
+
2b–18b–b
6
+
3–2
4
=
7a
4
–
17b
6
–
1
4
-
3
5
m
2
–2mn+
1
10
m
2
–
1
3
mn+2mn–2
m
2
=
(
3
5
m
2
+
1
10
m
2
–2
m
2
)
+(
–2mn
–
1
3
mn+
2mn
)=
6
m
2
+
m
2
–20
m
2
10
–
1
3
mn
=
–
m
2
–
1
3
mn
=
–
7
m
2
5
–
1
3
mn
-
–
3
4
a
2
+
1
10
ab–
5
6
b
2
+2
1
3
a
2
–
3
4
ab+
1
6
b
2
–
1
3
b
2
–2ab
=
(–
3
4
a
2
+
7
3
a
2
)
+(
1
10
ab–
3
4
ab–2ab
)
+(–
5
6
b
2
+
1
6
b
2
–
1
3
b
2
)=
–9
a
2
+28
a
2
12
+
2ab–15ab–40ab
20
+
–5
b
2
+
b
2
–2
b
2
6
=
19
a
2
12
–
53ab
20
–
b
2
-
0.4
x
2
y+31+
3
8
x
y
2
–0.6
y
3
–
2
5
x
2
y–0.2x
y
2
+
1
4
y
3
–6
=
(–
3
5
y
3
+
1
4
y
3
)
++(
3
8
x
y
2
–
1
5
x
y
2
)
+(31–6
)=
–12
y
3
+5
y
3
20
+
15x
y
2
–8x
y
2
40
+25
=
–
7
y
3
20
+
7x
y
2
40
+25
-
3
25
a
m–1
–
7
50
b
m–2
+
3
5
a
m–1
–
1
25
b
m–2
–0.2
a
m–1
+
1
5
b
m–2
=
(
3
25
a
m–1
+
3
5
a
m–1
–
1
5
a
m–1
)
+(–
7
50
b
m–2
–
1
25
b
m–2
+
1
5
b
m–2
)=
3
a
m–1
+15
a
m–1
–5
a
m–1
25
+
–7
b
m–2
–2
b
m–2
+10
b
m–2
50
=
13
a
m–1
25
+
b
m–2
50