- Ejercicio 13
problemas se debe reemplazar cada letra por su respectivo valor numérico
y realizar las operaciones correspondientes
1
2
, n=
2
3
,p=
1
4
, x=0
-
(
a+b
)
c–d=(1+2
)
3–4=3(
3
)
–4=9–4=5 -
(
a+b
)
(b–a
)
=(1+2
)
(2–1
)
=3(
1
)
=3 -
(b–m
)
(c–n
)
+4
a
2
=
(2–
1
2
)
(3–
2
3
)
+4(1
)
2
=
(
4–1
2
)
(
9–2
3
)
+4
=
3
2
(
7
3
)
+4
=
7
2
+4=
7+8
2
=
15
2
↔ 7
1
2
-
(2m+3n
)
(4p+
b
2
)=
(
2
1
2
+
3
2
3
)
(
4
1
4
+
2
2
)
=
(1+2
)
(1+4
)
=
3(
5
)
=
15
-
(4m+8p
)
(
a
2
+
b
2
)
(6n–d
)=
(
1
2
+
1
4
)
(
1
2
+
2
2
)
(
2
3
–4
)
=
=
0
-
(c–b
)
(d–c
)
(b–a
)
(m–p
)=
(3–2
)
(4–3
)
(2–1
)
(
1
2
–
1
4
)
=
(
1
)
(
1
)
(
1
)
(
2–1
4
)
=
1
4
-
b
2
(c+d
)
–
a
2
(m+n
)
+2x=
2
2
(3+4
)
–
1
2
(
1
2
+
2
3
)
+2(
0
)
=
4(
7
)
–(
3+4
6
)
=
28–
7
6
=
168–7
6
=
161
6
↔ 26
5
6
-
2mx+6(
b
2
+
c
2
)
–4
d
2
=
+6(
2
2
+
3
2
)
–4(4
)
2
=
6(
13
)
–64
=
78–64
=
14
-
(
8m
9n
+
16p
b
)
a=
(
1
2
2
3
+
1
4
2
)
(
1
)
=
(
+
2
)
=
2
3
+2=
2+6
3
=
8
3
↔ 2
2
3
-
x+m(
a
b
+
d
c
–
c
a
)=
0+
1
2
(
1
2
+
4
3
–
3
1
)
=
1
2
(1+64–3
)
=
2
=
31
-
4(m+p
)a
+
a
2
+
b
2
c
2
=
4(
1
2
+
1
4
)1
÷
1
2
+
2
2
3
2
=
4
(
2+1
4
)
÷
5
9
=
3 ÷
5
9
↔
3
5
9
=
27
5
↔ 5
2
5
-
(2m+3n+4p
)
(8p+6n–4m
)
(9n+20p
)=
(
2
1
2
+
3
2
3
+
4
1
4
)
(
1
4
+
2
3
–
1
2
)
(
2
3
+
1
4
)
=
(1+2+1
)
(
2
+4–
2
)
(6+5
)
=
(
4
)
(
4
)
(
11
)
=
176
-
c
2
(m+n
)
–
d
2
(m+p
)
+
b
2
(n+p
)=
3
2
(
1
2
+
2
3
)
–
4
2
(
1
2
+
1
4
)
+
2
2
(
2
3
+
1
4
)
=
(
3+4
)
–(
2+1
4
)
+
4
(
8+3
)
=
3(
7
2
)
–4(
3
)
+
11
3
=
21
2
–12+
11
3
=
63–72+22
6
=
13
6
↔ 2
1
6
-
(
c
2
+
d
2
a
÷
2
d
)
m=
(
c
2
+
d
2
a
2
d
)
m
=
(
3
2
+
4
2
1
2
4
)
1
2
=
(
25
2
2
)
1
2
=
5
2
↔ 2
1
2
-
(4p+2b
)
(18n–24p
)
+2(8m+2
)
(40p+a
)=
(
4
1
4
+2(
2
))
(
2
3
–
1
4
)
+2(
1
2
+2
)
(
1
4
+1
)
=
(1+4
)
(12–6
)
+2(4+2
)
(10+1
)
=
5(
6
)
+2(
6
)
(
11
)
=
30+132
=
162
-
a+
d
b
d–b
×
5+
2
m
2
p
2
=
1+
2
4–2
×
5+
2
(
1
2
)2
(
1
4
)2
=
3
2
×
5+
2
1
4
1
16
=
3
2
×
5+8
1
16
=
3
2
×
13
1
16
=
3
2
× 13(
=
312
-
(a+b
)
c
2
+8b
–m
n
2
=
(1+2
)
3
2
+8(
2
)–
1
2
(
2
3
)
2
=
3
9+16
–
1
2
(
2
3
)
=
3
25
–
1
3
=
3(
5
)
–
1
3
=
15–
1
3
=
45–1
3
=
44
3
↔ 14
2
3
-
(
a+c
2
+
6n
b
)
÷ (c+d
)p
=
(
1+3
2
+
2
3
2
)
÷ (3+4
)
1
4
=
(
4
2
+
4
2
)
÷ 7(
1
2
)
=
(
2
2
+
2
2
)
÷
7
2
=
2
7
2
=
4
7
-
3(c–b
)
32m
–2(d–a
)
16p
–
2
n
=
3(3–2
)
1
2
–2(4–1
)
1
4
–
2
2
3
=
3(
1
)
(
4
)
–2(
3
)
(
2
)
–3
=
12
–
12
–3
=
–3
-
6abc
2
8b
+
3mn
2(b–a
)–
cdnp
abc
=
6(
1
)
(
2
)
(
3
)
2
8(
2
)+
3
(
1
2
)
(
2
3
)
2(2–1
)–
3
(4
)
(
2
3
)
(
1
4
)
(
1
)
(2
)
(
3
)
=
36
2
16
+
1
2
–
1
3
=
2
(
4
)+(
3–2
6
)
=
3
4
+
1
6
=
9+2
12
=
11
12
-
a
2
+
b
2
b
2
–
a
2
+3(a+b
)
(2a+3b
)=
1
2
+
2
2
2
2
–
1
2
+3(1+2
)
(2 × 1+3 × 2
)
=
1+4
4–1
+3(
3
)
(2+6
)
=
5
3
+72=
5+216
3
=
221
3
↔ 73
2
3
-
b
2
+(
1
a
+
1
b
)
(
1
b
+
1
c
)
+
(
1
n
+
1
m
)2
=
2
2
+(
1
1
+
1
2
)
(
1
2
+
1
3
)
+
(
1
2
3
+
1
1
2
)2
=
4+(
2+1
2
)
(
3+2
6
)
+
(
3
2
+2
)2
=
4+(
3
2
)
(
5
)
+
(
3+4
2
)2
=
4+
5
4
+
(
7
2
)2
=
(
16+5
4
)
+
49
4
=
21
4
+
49
4
=
21+49
4
=
35
2
↔ 17
1
2
-
(2m+3n
)
(4p+2c
)
–4
m
2
n
2
=
(
2
1
2
+
3
2
3
)
(
4
1
4
+2 × 3
)
–4
(
1
2
)2
(
2
3
)2
=
(1+2
)
(1+6
)
–
4
(
1
4
)
(
4
9
)
=
3(
7
)
–
4
9
=
21–
4
9
=
189–4
9
=
185
9
↔ 20
5
9
-
b
2
–
c
3
2ab–m
–
n
b–m
=
2
2
–
3
3
2(
1
)
(
2
)
–
1
2
–
2
3
2–
1
2
=
4–1
4–
1
2
–
2
3
4–1
2
=
3
8–1
2
–
2
3
3
2
=
3
7
2
–
4
9
=
6
7
–
4
9
=
54–28
63
=
26
63