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Ejercicio 19

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CAPITULO I

Suma de polinomios
Ejercicio 19
Sumar las expresiones siguientes y hallar el valor numérico del resultado para a=2,b=3,c=10,x=5,y=4,m= 2 3 ,n= 1 5
Realizamos las sumas como los ejercicios anteriores, y en el resultado final reemplazamos los valores indicados de las letras para obtener el valor numerico
  1. 4x–5y;–3x+6y–8;–x+y 4x –5y – 3x +6y–8 – x +y ¯ 2y–8 = 2( 4 ) –8 = 8–8 = 0
  2. x 2 –5x+8;– x 2 +10x–30;–6 x 2 +5x–50 x 2 – 5x +8 – x 2 +10x–30 –6 x 2 + 5x –50 ¯ –6 x 2 +10x–72 = –6(5 ) 2 +10( 5 ) –72 = –6( 25 ) +50–72 = –150+50–72 = –172
  3. x 4 – y 4 ;–5 x 2 y 2 –8+2 x 4 ;–4 x 4 +7 x 3 y+10x y 3 x 4 – y 4 2 x 4 –5 x 2 y 2 –8 –4 x 4 +7 x 3 y+10x y 3 ¯ – x 4 +7 x 3 y–5 x 2 y 2 +10x y 3 – y 4 –8 = –(5 ) 4 +7(5 ) 3 ( 4 ) –5(5 ) 2 (4 ) 2 +10( 5 ) (4 ) 3 –(4 ) 4 –8 = –625+3500–2000+3200–256–8 = 3811
  4. 3m–5n+6;–6m+8–20n;–20n+12m–12 3m–5n+6 –6m–20n+8 12m–20n–12 ¯ 9m–45n+2 = ( 2 3 ) –( 1 5 ) +2 = 6–9+2 = –1
  5. nx+cn–ab;–ab+8nx–2cn;–ab+nx–5 –ab+cn– nx –ab–2cn+8nx –ab+ nx –5 ¯ –3ab–cn+8nx–5 = –3( 2 ) ( 3 ) –( ) ( 1 5 ) +8( 1 5 ) ( 5 ) –5 = –18–2+8–5 = –17

  6. 27 m 3 +125 n 3 ;–9 m 2 n+25m n 2 ;–14m n 2 –8;11m n 2 +10 m 2 n 27 m 3 +125 n 3 –9 m 2 n+25m n 2 –14m n 2 –8 10 m 2 n+11m n 2 ¯ 27 m 3 + m 2 n+22m n 2 +125 n 3 –8 = 27 ( 2 3 3 3 ) + ( 2 3 ) 2 ( 1 5 ) +22( 2 3 ) ( 1 5 ) 2 + 125 ( 1 5 3 ) –8 = 8 + 4 45 + 44 75 +1– 8 = 20+132+225 225 = 377 225 ⟺ 1 152 225

  7. n b–1 – m x–3 +8;–5 n b–1 –3 m x–3 +10;4 n b–1 +5 m x–3 –18 n b–1 – m x–3 + 8 – 5 n b–1 –3 m x–3 + 10 4 n b–1 +5 m x–3 – 18 ¯ m x–3 = ( 2 3 ) 5–3 = ( 2 3 ) 2 = 4 9


  8. 9 17 m 2 + 25 34 n 2 – 1 4 ;–15mn+ 1 2 ; 5 17 n 2 + 7 34 m 2 – 1 4 ;– 7 34 m 2 –30mn+3 9 17 m 2 + 25 34 n 2 – 1 4 –15mn+ 1 2 7 34 m 2 + 5 17 n 2 – 1 4 – 7 34 m 2 –30mn+3 ¯ 9 17 m 2 –45mn+( 25 n 2 +10 n 2 34 ) +3 = 9 17 m 2 –45mn+ 35 n 2 34 +3 = 9 17 ( 2 2 3 2 ) –( 2 3 ) ( 1 5 ) + 35 ( 1 5 ) 2 34 +3 = 4 17 –6+ ( 1 ) 34 +3 = 4 17 –3+ 7 170 = 40–510+7 170 = – 463 170 ↔ –2 123 170
  9. 1 2 b 2 m– 3 5 cn–2; 3 4 b 2 m+6– 1 10 cn;– 1 4 b 2 m+ 1 25 cn+4;2cn+ 3 5 – 1 8 b 2 m 1 2 b 2 m– 3 5 cn–2 3 4 b 2 m– 1 10 cn+6 – 1 4 b 2 m+ 1 25 cn+4 – 1 8 b 2 m+2cn+ 3 5 ¯ ( 4 b 2 m+6 b 2 m–2 b 2 m– b 2 m 8 ) +( –30cn–5cn+2cn+100cn 50 ) +( 8+ 3 5 ) = 7 b 2 m 8 + 67cn 50 + 43 5 = 7 (3 ) 2 2 3 + 67 5 0 ( 1 0 ) ( 1 5 ) + 43 5 = 21 4 + 67 25 + 43 5 = 525+268+860 100 = 1653 100 ↔ 16 53 100
  10. 0.2 a 3 +0.4a b 2 –0.5 a 2 b;–0.8 b 3 +0.6a b 2 –0.3 a 2 b;–0.4 a 3 +6–0.8 a 2 b;0.2 a 3 +0.9 b 3 +1.5 a 2 b 0.2 a 3 –0.5 a 2 b+0.4a b 2 –0.3 a 2 b+0.6a b 2 –0.8 b 3 – 0.4 a 3 –0.8 a 2 b+6 0.2 a 3 +1.5 a 2 b+0.9 b 3 ¯ –0.1 a 2 b+a b 2 +0.1 b 3 +6 = –0.1(2 ) 2 ( 3 ) +2(3 ) 2 +0.1(3 ) 3 +6 = –0.3( 4 ) +2( 9 ) +0.1( 27 ) +6 = –1.2+18+2.7+6 = 25.5
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