CAPITULO II
Resta
- Ejercicio 20
- Se identifican los términos de la resta es decir el minuendo y el sustraendo
- Restamos del minuendo el sustraendo cambiando su signo cambiado
- Se reduce las cantiades semejantes
De:
- -8 restar 5
-8-5=-13
- -7 restar 4
-7-4=-11
- 8 restar 11
8-11=-3
- -8 restar -11
-8-(-11)=-8+11=3
- -1 restar -9
-1-(-9)=-1+9=8
-
2a
restar
3b
2a–3b
-
3b
restar
2
3b–2
-
4x
restar
6b
4x–6b
-
–5a
restar
6b
–5a–6b
-
–8x
restar
–3
–8x–( –3 ) =–8x+3
-
–9
a
2
restar
5
b
2
–9 a 2 –5 b 2
-
–7xy
restar
–5yz
–7xy–( –5yz ) =–7xy+5yz
-
3a
restar
4a
3a–4a=–a
-
11
m
2
restar
25
m
2
11 m 2 –25 m 2 =–14 m 2
-
–6
x
2
y
restar
–
x
2
y
–6 x 2 y–( – x 2 y ) =–6 x 2 y+ x 2 y=–5 x 2 y
-
11
a
3
m
2
restar
–7
a
3
m
2
11 a 3 m 2 –( –7 a 3 m 2 ) =11 a 3 m 2 +7 a 3 m 2 =18 a 3 m 2
-
–8a
b
2
restar
–8a
b
2
–8a b 2 –( –8a b 2 ) =– 8a b 2 + 8a b 2 =0
-
31
x
2
y
restar
–46
x
2
y
31 x 2 y–( –46 x 2 y ) =31 x 2 y+46 x 2 y=77 x 2 y
-
–84
a
2
b
restar
–84
a
2
b
–84 a 2 b–( –84 a 2 b ) =– 84 a 2 b + 84 a 2 b =0
-
3
a
x+1
restar
5
b
x+2
3 a x+1 – 5 b x+2
-
–8
x
a+2
restar 11
–8 x a+2 –11
-
6
a
n
restar
–5
a
n
6 a n –( –5 a n ) =6 a n +5 a n =11 a n
-
–45
a
x–1
restar
–60
a
x–1
–45 a x–1 –( –60 a x–1 ) =–45 a x–1 +60 a x–1 =15 a x–1
-
54
b
n–1
restar
–86
b
n–1
54 b n–1 –( –86 b n–1 ) =54 b n–1 +86 b n–1 =140 b n–1
-
–35
m
a
restar
–60
m
a
–35 m a –( –60 m a ) =–35 m a +60 m a =25 m a
- 5 restar
–
1
2
5–( – 1 2 ) =5+ 1 2 = 10+1 2 = 11 2
-
–
2
3
restar
–
3
4
– 2 3 –( – 3 4 ) =– 2 3 + 3 4 = –8+9 12 = 1 12
-
1
3
x
2
restar
–
2
3
x
2
1 3 x 2 –( – 2 3 x 2 ) = 1 3 x 2 + 2 3 x 2 = x 2 +2 x 2 3 = 3 x 2 3 = x 2
-
4
5
x
3
y
restar
–
5
6
x
3
y
4 5 x 3 y–( – 5 6 x 3 y ) = 4 5 x 3 y+ 5 6 x 3 y= 24 x 3 y+25 x 3 y 30 = 49 30 x 3 y
-
–
1
8
a
b
2
restar
–
3
4
a
b
2
– 1 8 a b 2 –( – 3 4 a b 2 ) =– 1 8 a b 2 + 3 4 a b 2 = –a b 2 +6a b 2 8 = 5 8 a b 2
Restar
-
3de–2
–2–3=–5
-
–1de7
7–( –1 ) =7+1=8
-
–5de–8
–8–( –5 ) =–8+5=–3
-
–4de5
5–( –4 ) =5+4=9
-
–7de–7
–7–( –7 ) =– 7 + 7 =0
-
–5de2a
2a–( –5 ) =2a+5
-
bde–3x
–3x–b
-
5mde–2n
–2n–5m
-
–6ade3b
3b–( –6a ) =3b+6a
-
–5
a
3
de8b
8b–( –5 a 3 ) =8b+5 a 3
-
–9de–7a
–7a–( –9 ) =–7a+9
-
–25de25ab
25ab–( –25 ) =25ab+25
-
–ade3a
3a–( –a ) =3a+a
-
–3bde–4b
–4b–( –3b ) =–4b+3b
-
–11
x
3
de54
x
3
54 x 3 –( –11 x 3 ) =54 x 3 +11 x 3 =65 x 3
-
14
a
2
bde78
a
2
b
78 a 2 b–14 a 2 b=64 a 2 b
-
–43
a
2
yde–54
a
2
y
–54 a 2 y–( –43 a 2 y ) =–54 a 2 y+43 a 2 y=–11 a 2 y
-
9abde–ab
–ab–9ab=–10ab
-
–31
x
2
yde–31
x
2
y
–31 x 2 y–( –31 x 2 y ) =– 31 x 2 y + 31 x 2 y =0
-
a
x
de–3
a
x
–3 a x – a x =–4 a x
-
–7
a
x+1
de311
a
x+1
311 a x+1 –( –7 a x+1 ) =311 a x+1 +7 a x+1 =318 a x+1
-
9
m
x
de105
m
x
105 m x –9 m x =94 m x
-
18
a
x–1
de–31
a
x–1
–31 a x–1 –18 a x–1 =–49 a x–1
-
–19
m
a
de–236
m
a
–236 m a –( –19 m a ) =–236 m a +19 m a =–217 m a
-
54
a
x+2
de–85
a
x+2
–85 a x+2 –54 a x+2 =–139 a x+2
-
–6ade
1
4
1 4 –( –6a ) = 1 4 +6a
-
–5de–
2
3
– 2 3 –( –5 ) =– 2 3 +5= –2+15 3 = 13 3
-
3
8
m
3
de–
7
10
m
3
– 7 10 m 3 – 3 8 m 3 = –28 m 3 –15 m 3 40 =– 43 40 m 3
-
–
11
12
a
2
b
2
de
5
6
a
2
b
2
5 6 a 2 b 2 –( – 11 12 a 2 b 2 ) = 5 6 a 2 b 2 + 11 12 a 2 b 2 = 10 a 2 b 2 +11 a 2 b 2 12 = a 2 b 2 = 7 4 a 2 b 2
-
45
a
3
b
2
de–
1
9
a
3
b
2
– 1 9 a 3 b 2 –45 a 3 b 2 = – a 3 b 2 –405 a 3 b 2 9 =– 406 9 a 3 b 2 =–45 1 9 a 3 b 2