Ejercicio 227

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CAPITULO XXX

TEORIA DE LOS EXPONENTES
Ejercicio 227
Hallar el valor de:
  1. ( a 1 ) 2 = a 1( 2 ) = a 2
  2. ( a 2 b 1 ) 3 = a 2( 3 ) b 1( 3 ) = a 6 b 3
  3. ( a 3 2 ) 2 = a 3 2 (2 ) = a 3
  4. ( x 3 4 ) 3 = x 3 4 ( 3 ) = x 9 4
  5. ( m 3 4 ) 2 = m 3 (2 ) = m 3 2
  6. ( a 2 3 ) 3 = a 2 3 (3 ) = a 2
  7. ( x 4 y 1 4 ) 2 = x 4( 2 ) y 1 (2 ) = x 8 y 1 2
  8. (2 a 1 2 b 1 3 ) 2 = 2 2 a 1 2 (2 ) b 1 3 ( 2 ) =4a b 2 3
  9. ( a 3 b 1 ) 4 = a 3( 4 ) b 1( 4 ) = a 12 b 4
  10. ( x 2 3 y 1 2 ) 6 = x 2 3 () y 1 2 () = x 4 y 3
  11. (3 a 2 5 b 3 ) 5 = 3 5 a 2 5 (5 ) b 3( 5 ) =243 a 2 b 15
  12. (2 m 1 2 n 1 3 ) 3 = 2 3 m 1 2 ( 3 ) n 1 3 (3 ) =8 m 3 2 n 1