Ejercicio 256 – Solucionario Baldor

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CAPITULO XXXII

CANTIDADES IMAGINARIAS

Dividir:

$\begin{matrix} \sqrt{- 16} \div \sqrt{- 4} & = \sqrt{\frac{-}{- 4}} \\ = \sqrt{4} \\ = 2 \end{matrix}$
$\begin{matrix} \sqrt{- 10} \div \sqrt{- 2} & = \sqrt{\frac{-}{- 2}} \\ = \sqrt{5} \end{matrix}$
$\begin{matrix} \sqrt{- 81} \div \sqrt{- 3} & = \sqrt{\frac{-}{- 3}} \\ = \sqrt{27} \\ = \sqrt{3^{3}} \\ = 3 \sqrt{3} \end{matrix}$
$\begin{matrix} \sqrt{- 90} \div \sqrt{- 5} & = \sqrt{\frac{-}{- 5}} \\ = \sqrt{18} \\ = \sqrt{2. 3^{2}} \\ = 3 \sqrt{2} \end{matrix}$
$\begin{matrix} \sqrt{- 150} \div \sqrt{- 3} & = \sqrt{\frac{-}{- 3}} \\ = \sqrt{50} \\ = \sqrt{2. 5^{2}} \\ = 5 \sqrt{2} \end{matrix}$
$\begin{matrix} 10 \sqrt{- 36} \div 5 \sqrt{- 4} & = \frac{}{5} \sqrt{\frac{-}{- 4}} \\ = 2 \sqrt{9} \\ = 2 (3) \\ = 6 \end{matrix}$
$\begin{matrix} 2 \sqrt{- 18} \div \sqrt{- 6} & = 2 \sqrt{\frac{-}{- 6}} \\ = 2 \sqrt{3} \end{matrix}$
$\begin{matrix} \sqrt{- 315} \div \sqrt{- 7} & = \sqrt{\frac{-}{- 7}} \\ = \sqrt{45} \\ = \sqrt{5. 3^{2}} \\ = 3 \sqrt{5} \end{matrix}$
$\begin{matrix} \sqrt[4]{- 27} \div \sqrt[4]{- 3} & = \sqrt[4]{\frac{-}{- 3}} \\ = \sqrt[4]{9} \\ = 3^{2} \\ = \sqrt{3} \end{matrix}$
$\begin{matrix} \sqrt[4]{- 300} \div \sqrt[4]{- 12} & = \sqrt[4]{\frac{-}{- 12}} \\ = \sqrt[4]{25} \\ = 5^{2} \\ = \sqrt{5} \end{matrix}$