▶️ Ejercicio 257 álgebra - Solucionario Baldor ✅✅

Comparte esto 👍👍

DESCARGA

CAPITULO XXXII

CANTIDADES IMAGINARIAS

Ejercicio 257

Sumar:

$\begin{matrix} 2 + 3 \sqrt{- 1}, 5 - 2 \sqrt{- 1} \\ 2 + 3 \sqrt{- 1} + 5 - 2 \sqrt{- 1} & = 2 + 3 i + 5 - 2 i \\ = 7 + i \end{matrix}$
$\begin{matrix} - 4 - 5 \sqrt{- 1}, - 2 + 8 \sqrt{- 1} \\ - 4 - 5 \sqrt{- 1} - 2 + 8 \sqrt{- 1} & = - 4 - 5 i - 2 + 8 i \\ = - 6 \end{matrix}$
$\begin{matrix} 12 - 11 \sqrt{- 1}, 8 + 7 \sqrt{- 1} \\ 12 - 11 \sqrt{- 1} + 8 + 7 \sqrt{- 1} & = 12 - 11 i + 8 + 7 i \\ = 20 - 4 i \end{matrix}$
$\begin{matrix} 5 + \sqrt{- 1}, 7 + 2 \sqrt{- 1}, 9 + 7 \sqrt{- 1} \\ 5 + \sqrt{- 1} + 7 + 2 \sqrt{- 1} + 9 + 7 \sqrt{- 1} & = 5 + i + 7 + 2 i + 9 + 7 i \\ = 21 + 8 i \end{matrix}$
$\begin{matrix} 3 - 2 i, 5 - 8 i, - 10 + 13 i \\ 3 - 2 i + 5 - 8 i - 10 + 13 i & = - 2 + 3 i \end{matrix}$
$\begin{matrix} 1 - i, 4 + 3 i, \sqrt{2} + 5 i \\ 1 - i + 4 + 3 i + \sqrt{2} + 5 i & = \sqrt{2} + 5 + 8 i \end{matrix}$
$\begin{matrix} 2 + \sqrt{- 2}, 4 - \sqrt{- 3} \\ 2 + \sqrt{- 2} + 4 - \sqrt{- 3} & = 2 + \sqrt{(- 1) (2)} + 4 - \sqrt{(- 1) (3)} \\ = 6 + \sqrt{- 1} \sqrt{2} - \sqrt{- 1} \sqrt{3} \\ = 6 + \sqrt{2} i - \sqrt{3} i \\ = 6 + (\sqrt{2} - \sqrt{3}) i \end{matrix}$
$\begin{matrix} 7 + \sqrt{- 5}, \sqrt{2} - \sqrt{- 9}, - 4 + \sqrt{- 16} \\ 7 + \sqrt{- 5} + \sqrt{2} - \sqrt{- 9} - 4 + \sqrt{- 16} & = 7 + \sqrt{(- 1) (5)} + \sqrt{2} - \sqrt{(- 1) (3^{2})} - 4 + \sqrt{(- 1) (4^{2})} \\ = 3 + \sqrt{- 1} \sqrt{5} + \sqrt{2} - 3 \sqrt{- 1} + 4 \sqrt{- 1} \\ = 3 + \sqrt{5} i + \sqrt{2} - 3 i + 4 i \\ = 3 + \sqrt{2} + \sqrt{5} i + i \\ = 3 + \sqrt{2} + (\sqrt{5} + 1) i \end{matrix}$