- Ejercicio 7
basta realizar la suma algebraica de los coeficientes de los términos
que tengan la misma parte literaria:
-
x+2x=3x
-
8a+9a=17a
-
11b+9b=20b
-
–b–5b=–6b
-
–9m–7m=–16m
-
–8m–m=–9m
-
4
a
x
+5
a
x
=9
a
x
-
6a
x+1
+8a
x+1
=14a
x+1
-
–m
x+1
–5m
x+1
=–6m
x+1
-
–3a
x–2
–a
x–2
=–4a
x–2
-
1
2
a+
1
2
a=
a+a
2
=
2a
2
=a
-
3
5
ab+
1
10
ab=
6ab+ab
10
=
7ab
10
-
1
3
xy+
1
6
xy=
2xy+xy
6
=
3xy
6
=
xy
2
-
–
1
5
xy–
4
5
xy=
–xy–4xy
5
=–
5xy
5
=–xy
-
–
5
6
a
2
b–
1
8
a
2
b=
–20
a
2
b–3
a
2
b
24
=–
23
a
2
b
24
-
–a–
7
8
a=
–8a–7a
8
=–
15a
8
-
8a+9a+6a+=23a
-
15x+20x+x=36x
-
–7m–8m–9m=–24m
-
–
a
2
b–
a
2
b–3
a
2
b=–5–
a
2
b
-
a
x
+3
a
x
+8
a
x
=12
a
x
-
–5
a
x+1
–3
a
x+1
–5
a
x+1
=–13
a
x+1
-
a+
1
2
a+
2
3
a=
6a+3a+4a
6
=
13a
6
-
–x–
2
3
x–
1
6
x=
–6x–4x–x
6
=–
11x
6
-
1
5
ax+
3
10
ax+ax=
2ax+3ax+10ax
10
=
15ax
10
=
3ax
2
-
–
3
4
a
2
x–
5
6
a
2
x–
a
2
x=
–9
a
2
x–10
a
2
x–12
a
2
x
12
=–
31
a
2
x
12
-
11a+8a+9a+11a=39a
-
m
x+1
+3m
x+1
+4m
x+1
+6m
x+1
=14m
x+1
-
–x
2
y–8x
2
y–9x
2
y–20x
2
y=–38x
2
y
-
–3a
m
–5a
m
–6a
m
–9a
m
=–23a
m
-
1
2
a+
1
4
a+
1
8
a+a=
4a+2a+a+8a
8
=
15a
8
-
2
5
ax+
1
2
ax+
1
10
ax+
1
20
ax=
8ax+10ax+2ax+ax
20
=
21ax
20
-
0.5m+0.6m+0.7m+0.8m=2.6m
-
–
1
7
ab–
1
14
ab–
1
28
ab–ab=
–4ab–2ab–ab–28ab
28
=–
35ab
28
=–
5ab
4
-
–
2
3
x
3
y–
1
6
x
3
y–
1
9
x
3
y–
1
12
x
3
y=
–24
x
3
y–6
x
3
y–4
x
3
y–3
x
3
y
36
=–
37
x
3
y
36
-
ab
2
+ab
2
+7ab
2
+9ab
2
+21ab
2
=39ab
2
-
–m–m–8m–7m–3m=–20m
-
–x
a+1
–8x
a+1
–4x
a+1
–5x
a+1
–x
a+1
=–19x
a+1
-
1
2
a+
1
3
a+
1
4
a+
1
5
a+
1
6
a=
30a+20a+15a+12a+10a
60
=
87
60
a=
29
20
a
-
–
1
3
ab–
1
6
ab–
1
2
ab–
1
12
ab–
1
9
ab=
–12ab–6ab–18ab–3ab–4ab
36
=–
43
36
ab