- Ejercicio 8
ejercicios basta realizar la suma algebraica de los coeficientes de los
términos que tengan la misma parte literaria:
-
8a–6a=2a
-
6a–8a=–2a
-
9ab–15ab=–6ab
-
15ab–9ab=6ab
-
2a–2a=0
-
–7b+7b=0
-
–14xy+32xy=18xy
-
–25x
2
y+32x
2
y=7x
2
y
-
40x
3
y–51
x
3
y=–11x
3
y
-
–
m
2
n+6
m
2
n=5
m
2
n
-
–15xy+40xy=25xy
-
55
a
3
b
2
–81
a
3
b
2
=–26
a
3
b
2
-
–
x
2
y+
x
2
y=0
-
–9a
b
2
+9a
b
2
=0
-
7
x
2
y–7
x
2
y=0
-
–101mn+118mn=17mn
-
502ab–405ab=97ab
-
–1024x+1018x=–6x
-
–15ab+15ab=0
-
1
2
a–
3
4
a=
2a–3a
4
=–
1
4
a
-
3
4
a–
1
2
a=
3a–2a
4
=
a
4
-
5
6
a
2
b–
5
12
a
2
b=
10
a
2
b–5
a
2
b
12
=
5
a
2
b
12
-
–
4
7
x
2
y+
9
14
x
2
y=
–8
x
2
y+9
x
2
y
14
=
x
2
y
14
-
3
8
am–
5
4
am=
3am–10am
8
=
–7am
8
-
–am+
3
5
am=
–5am+3am
5
=–
2am
5
-
5
6
mn–
7
8
mn=
21mn–20mn
24
=–
mn
24
-
–
a
2
b+
3
11
a
2
b=
–11
a
2
b+3
a
2
b
11
=–
8
a
2
b
11
-
3.4
a
4
b
3
–5.6
a
4
b
3
=–2.2
a
4
b
3
-
–1.2yz+3.4yz=2.2yz
-
4
a
x
–2
a
x
=2
a
x
-
–8
a
x+1
+8
a
x+1
=0
-
25
m
a–1
–32
m
a–1
=–7
m
a–1
-
–
x
a+1
+
x
a+1
=0
-
–
1
4
a
m–2
+
1
2
a
m–2
=
–
a
m–2
+2
a
m–2
4
=
a
m–2
4
-
5
6
a
m+1
–
7
12
a
m+1
=
10
a
m+1
–7
a
m+1
12
=
3
a
m+1
12
=
a
m+1
4
-
4
a
2
–
1
3
a
2
=
12
a
2
–
a
2
3
=
11
a
2
3
-
–5mn+
3
4
mn=
–20mn+3mn
4
=–
17mn
4
-
8
a
x+2
b
x+3
–25
a
x+2
b
x+3
=–17
a
x+2
b
x+3
-
–
7
8
a
m
b
n
+
a
m
b
n
=
–7
a
m
b
n
+8
a
m
b
n
8
=
a
m
b
n
8
-
0.85mxy–
1
2
mxy=0.85mxy–0.5mxy=0.35mxy