- Ejercicio 10
problemas se tiene que agrupar todos los terminos de la misma clase, se
reducen los términos de cada clase y obtenemos el polinomio resultante
-
7 a – 9 b + 6 a – 4 b = ( – 9 b – 4 b
)
+ ( 7 a + 6 a
)
= 13 a – 13 b -
a + b – c – b – c + 2 c – a = + + = 0
-
5 x – 11 y – 9 + 20 x – 1 – y = ( 5 x + 20 x
)
+ ( – 11 y – y
)
+ ( – 9 – 1
)
= 25 x – 12 y – 10 -
– 6 m + 8 n + 5 – m – n – 6 m – 11 = ( – 6 m – m
)
+ ( 8 n – n
)
+ ( 5 – 11
)
= – 7 m + 7 n – 6 -
– a + b + 2 b – 2 c + 3 a + 2 c – 3 b = ( – a + 3 a
)
+ + = 2 a -
– 81 x + 19 y – 30 z + 6 y + 80 x + x – 25 y = + – 30 z = – 30 z
-
15
a
2
– 6 a b – 8
a
2
+ 20 – 5 a b – 31 +
a
2
– a b = ( 15
a
2
– 8
a
2
+
a
2
)
+ ( – 6 a b – a b – 5 a b
)
+ ( 20 – 31
)
= 8
a
2
– 12 a b – 11 -
– 3 a + 4 b – 6 a + 81 b – 114 b + 31 a – a – b = ( – 3 a – 6 a + 31 a – a
)
+ ( 4 b + 81 b – 114 b – b
)
= 21 a – 30 -
– 71
a
3
b – 84
a
4
b
2
+ 50
a
3
b + 84
a
4
b
2
– 45
a
3
b + 18
a
3
b = + ( – 71
a
3
b + 50
a
3
b – 45
a
3
b + 18
a
3
b
)
= – 48
a
3
b -
– a + b – c + 8 + 2 a + 2 b – 19 – 2 c – 3 a – 3 – 3 b + 3 c = + + + ( 8 – 19 – 3
)
= – 14 -
m
2
+ 71 m n – 14
m
2
– 65 m n +
m
3
–
m
2
– 115
m
2
+ 6
m
3
= (
m
3
+ 6
m
3
)
+ (
m
2
– 14
m
2
–
m
2
– 115
m
2
)
+ ( 71 m n – 65 m n
)
= 7
m
3
– 129
m
2
+ 6 m n -
x
4
y –
x
3
y
2
+
x
2
y – 8
x
4
y –
x
2
y – 10 +
x
3
y
2
– 7
x
3
y
2
– 9 + 21
x
4
y –
y
3
+ 50
=
(
x
4
y – 8
x
4
y + 21
x
4
y
)
+ ( –
x
3
y
2
+
x
3
y
2
– 7
x
3
y
2
)
+ (
x
2
y
–
x
2
y
)
–
y
3
+ ( – 10 – 9 + 50
) =
14
x
4
y – 7
x
3
y
2
–
y
3
+ 31
-
5
a
x + 1
– 3
b
x + 2
– 8
c
x + 3
– 5
a
x + 1
– 50 + 4
b
x + 2
– 65 –
b
x + 2
+ 90 +
c
x + 3
+ 7
c
x + 3
=
+ + + ( – 50 – 65 + 90
) =
– 25
-
a
m + 2
–
x
m + 3
– 5 + 8 – 3
a
m + 2
+ 5
x
m + 3
– 6 +
a
m + 2
– 5
x
m + 3
=
(
a
m + 2
– 3
a
m + 2
+
a
m + 2
)
+ ( 5
x
m + 3
–
x
m + 3
– 5
x
m + 3
)
+ ( – 5 + 8 – 6
) =
–
a
m + 2
–
x
m + 3
– 3
-
0.3 a + 0.4 b + 0.5 c – 0.6 a – 0.7 b – 0.9 c + 3 a – 3 b – 3 c
=
( 0.3 a – 0.6 a + 3 a
)
+ ( 0.4 b – 0.7 b – 3 b
)
+ ( 0.5 c – 0.9 c – 3 c
) =
2.7 a – 3.3 b – 3.4 c
-
1
2
a +
1
3
b + 2 a – 3 b –
3
4
a –
1
6
b +
3
4
–
1
2
=
(
1
2
a + 2 a –
3
4
a
)
+ (
1
3
b – 3 b –
1
6
b
)
+ (
3
4
–
1
2
)
=
2 a + 8 a – 3 a
4
+
2 b – 18 b – b
6
+
3 – 2
4
=
7 a
4
–
17 b
6
–
1
4
-
3
5
m
2
– 2 m n +
1
10
m
2
–
1
3
m n + 2 m n – 2
m
2
=
(
3
5
m
2
+
1
10
m
2
– 2
m
2
)
+ (
– 2 m n
–
1
3
m n +
2 m n
) =
6
m
2
+
m
2
– 20
m
2
10
–
1
3
m n
=
–
m
2
–
1
3
m n
=
–
7
m
2
5
–
1
3
m n
-
–
3
4
a
2
+
1
10
a b –
5
6
b
2
+ 2
1
3
a
2
–
3
4
a b +
1
6
b
2
–
1
3
b
2
– 2 a b
=
( –
3
4
a
2
+
7
3
a
2
)
+ (
1
10
a b –
3
4
a b – 2 a b
)
+ ( –
5
6
b
2
+
1
6
b
2
–
1
3
b
2
) =
– 9
a
2
+ 28
a
2
12
+
2 a b – 15 a b – 40 a b
20
+
– 5
b
2
+
b
2
– 2
b
2
6
=
19
a
2
12
–
53 a b
20
–
b
2
-
0.4
x
2
y + 31 +
3
8
x
y
2
– 0.6
y
3
–
2
5
x
2
y – 0.2 x
y
2
+
1
4
y
3
– 6
=
( –
3
5
y
3
+
1
4
y
3
)
+ + (
3
8
x
y
2
–
1
5
x
y
2
)
+ ( 31 – 6
) =
– 12
y
3
+ 5
y
3
20
+
15 x
y
2
– 8 x
y
2
40
+ 25
=
–
7
y
3
20
+
7 x
y
2
40
+ 25
-
3
25
a
m – 1
–
7
50
b
m – 2
+
3
5
a
m – 1
–
1
25
b
m – 2
– 0.2
a
m – 1
+
1
5
b
m – 2
=
(
3
25
a
m – 1
+
3
5
a
m – 1
–
1
5
a
m – 1
)
+ ( –
7
50
b
m – 2
–
1
25
b
m – 2
+
1
5
b
m – 2
) =
3
a
m – 1
+ 15
a
m – 1
– 5
a
m – 1
25
+
– 7
b
m – 2
– 2
b
m – 2
+ 10
b
m – 2
50
=
13
a
m – 1
25
+
b
m – 2
50