Ejercicio 250

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CAPITULO XXXI

R a d i c a l e s
División de radicales cuando el divisor es compuesto
Ejercicio 250
Dividir:
  1. 2 entre 2 + 3 2 2 + 3 = 2 2 + 3 × 2 3 2 3 = 2 6 23 = 2 6 1 = 6 2
  2. 3 entre 3 2 5 3 3 2 5 = 3 3 2 5 × 3 +2 5 3 +2 5 = 3+2 15 (3 ) 2 (2 5 ) 2 = 3+2 15 34( 5 ) = 3+2 15 320 = 3+2 15 17
  3. 2+ 5 entre1 5 2+ 5 1 5 = 2+ 5 1 5 × 1+ 5 1+ 5 = 2+ 5 +2 5 +5 1 (5 ) 2 = 7+3 5 15 = 7+3 5 4 = 7+3 5 4
  4. 2 + 5 entre 2 5 2 + 5 2 5 = 2 + 5 2 5 × 2 + 5 2 + 5 = ( 2 + 5 ) 2 (2 ) 2 (5 ) 2 = 2+2 10 +5 25 = 7+2 10 3
  5. 2 3 7 entre 3 + 7 2 3 7 3 + 7 = 2 3 7 3 + 7 × 3 7 3 7 = 2 3 2 21 2 21 + 7 2 (3 ) 2 (7 ) 2 = 2( 3 ) 3 21 +7 37 = 63 21 +7 4 = 3 21 13 4
  6. 6 +2 5 entre2 6 5 6 +2 5 2 6 5 = 6 +2 5 2 6 5 × 2 6 + 5 2 6 + 5 = 2( 6 ) +4 30 + 30 +2( 5 ) (2 6 ) 2 (5 ) 2 = 12+5 30 +10 4( 6 ) 5 = 22+5 30 19
  7. 5 2 +3 3 entre3 2 4 3 5 2 +3 3 3 2 4 3 = 5 2 +3 3 3 2 4 3 × 3 2 +4 3 3 2 +4 3 = 15 2 2 +9 6 +20 6 +12 3 2 (3 2 ) 2 (4 3 ) 2 = 15( 2 ) +29 6 +12( 3 ) 9( 2 ) 16( 3 ) = 30+29 6 +36 1848 = 66+29 6 30
  8. 7 2 11 entre2 7 + 11 7 2 11 2 7 + 11 = 7 2 11 2 7 + 11 × 2 7 11 2 7 11 = 2 7 2 77 4 77 +2 1 1 2 (2 7 ) 2 (11 ) 2 = 2( 7 ) 5 77 +2( 11 ) 4( 7 ) 11 = 145 77 +22 2811 = 365 77 17