▶️ Ejercicio 69 álgebra - Solucionario Baldor ✅✅

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CAPITULO VI

PRODUCTOS Y COCIENTES NOTABLES

Escribir por simple inspección el resultado de:

$\frac{x^{2} - 1}{x + 1} = x - 1$
$\frac{1 - x^{2}}{1 - x} = 1 + x$
$\frac{x^{2} - y^{2}}{x + y} = x - y$
$\frac{y^{2} - x^{2}}{y - x} = y + x$
$\frac{x^{2} - 4}{x + 2} = x - 2$
$\frac{9 - x^{4}}{3 - x^{2}} = 3 + x^{2}$
$\frac{a^{2} - 4 b^{2}}{a + 2 b} = a - 2 b$
$\frac{25 - 36 x^{4}}{5 - 6 x^{2}} = 5 + 6 x^{2}$
$\frac{4 x^{2} - 9 m^{2} n^{4}}{2 x + 3 m n^{2}} = 2 x - 3 m n^{2}$
$\frac{36 m^{2} - 49 n^{2} x^{4}}{6 m - 7 n x^{2}} = 6 m + 7 n x^{2}$
$\frac{81 a^{6} - 100 b^{8}}{9 a^{3} + 10 b^{4}} = 9 a^{3} - 10 b^{4}$
$\frac{a^{4} b^{6} - 4 x^{8} y^{10}}{a^{2} b^{3} + 2 x^{4} y^{5}} = a^{2} b^{3} - 2 x^{4} y^{5}$
$\frac{x^{2 n} - y^{2 n}}{x^{n} + y^{n}} = x^{n} - y^{n}$
$\frac{a^{2 x + 2} - 100}{a^{x + 1} - 10} = a^{x + 1} + 10$
$\frac{1 - 9 x^{2 m + 4}}{1 + 3 x^{m + 2}} = 1 + 3 x^{m + 2}$
$\frac{{(x + y)}^{2} - z^{2}}{(x + y) - z} = (x + y) + z = x + y + z$
$\frac{1 - {(a + b)}^{2}}{1 + (a + b)} = 1 - (a + b) = 1 - a - b$
$\frac{4 - {(m + n)}^{2}}{2 + (m + n)} = 2 - (m + n) = 2 - m - n$
$\frac{x^{2} - {(x - y)}^{2}}{x + (x + y)} = x - (x + y) = y$
$\frac{{(a + x)}^{2} - 9}{(a + x) + 3} = (a + x) - 3 = a + x - 3$