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DESCARGA
CAPITULO II

Resta de polinomios y valor numérico
Ejercicio 26
  • Se identifican tanto el minuendo como sustraendo
  • Se escribe el minuendo con su propio signo y se cambia el signo del sustraendo
  • En la respuesta se sustituye cada letra por su respectivo valor numérico
Efectuar las restas siguientes y hallar el valor numérico del resultado para a = 1, b = 2, c = 3, x = 4, y = 5, m = 3 2 , n = 2 5 .

De:
  1. Mathematical Equation

  2. Mathematical Equation

  3. 1 2 arestar 1 2 b– 5 3 c+a 1 2 a–( 1 2 b– 5 3 c+a ) = 1 2 a– 1 2 b+ 5 3 c–a = ( 1 2 a–a ) – 1 2 b+ 5 3 c = a–2a 2 – 1 2 b+ 5 3 c = – a 2 – 1 2 b+ 5 3 c = – 1 2 – 1 2 (2 ) + 5 3 (3 ) = – 1 2 –1+5 = –1–2+10 2 = 7 2
  4. 3 m 2 –5 n 2 restar m 2 +8mn+10 n 2 3 m 2 –5 n 2 – m 2 –8mn–10 n 2 ¯ 2 m 2 –8mn–15 n 2 = 2 ( 3 2 ) 2 –8( 3 2 ) ( 2 5 ) –15 ( 2 5 ) 2 = 2 ( 9 ) – 24 5 –( 4 ) = 9 2 – 25 5 – 12 5 = 45–50–24 10 = – 29 10
  5. Mathematical Equation

  6. Mathematical Equation

  7. Mathematical Equation
  8. Mathematical Equation

  9. Restar:
    Mathematical Equation

  10. 15abde–ab+10mn–8mx –ab+10mn–8mx–15ab = –16ab+10mn–8mx = –16( 1 ) ( 2 ) +( 3 2 ) ( 2 5 ) –( 3 2 ) 4 = –32+6–48 = –74
  11. 11 a 2 b–9a b 2 + b 3 de a 3 a 3 –(11 a 2 b–9a b 2 + b 3 ) = a 3 –11 a 2 b+9a b 2 – b 3 = 1 3 –11(1 ) 2 ( 2 ) +9( 1 ) (2 ) 2 – 2 3 = 1–22+36–8 = 7
  12. 2 3 x 2 + 5 6 x– 3 8 de 1 63 x 4 1 64 x 4 –( 2 3 x 2 + 5 6 x– 3 8 ) = 1 64 x 4 – 2 3 x 2 – 5 6 x+ 3 8 = 1 64 (4 ) 4 – 2 3 (4 ) 2 – 5 () + 3 8 = 1 4 3 (4 ) 4 – 2 3 ( 16 ) – 10 3 + 3 8 = 4– 32 3 – 10 3 + 3 8 = 96–256–80+9 24 = – = – 77 8 ↔ –9 5 8
  13. Mathematical Equation

  14. Mathematical Equation
Categories: Capítulo II